That would be 6 just put the the whole number over one and keep flip change
Answer:
9.52
Step-by-step explanation:
Answer:
Not quite sure what you're meant to solve for, but my solution is below.
Step-by-step explanation:
The square root of a value squared is the absolute value of that value, because squaring removes all negatives. Therefore:
![\sqrt{(y+2)^2}=c](https://tex.z-dn.net/?f=%5Csqrt%7B%28y%2B2%29%5E2%7D%3Dc)
![\mid y+2\mid=c](https://tex.z-dn.net/?f=%5Cmid%20y%2B2%5Cmid%3Dc)
![\mid y\mid =c-2](https://tex.z-dn.net/?f=%5Cmid%20y%5Cmid%20%3Dc-2)
Hope this helps!
Answer:
None of the options is correct
Step-by-step explanation:
It is important to know that he expression a < x < b means that x is greater than a and less than b. So, for finding the correct value let's analyse each option.
A. 4 < 50 < 5
50 is greater than 4 but it is not less than 5, so, option A is incorrect.
B. 7 < 50 < 8
50 is greater than 7 but it is not less than 8, so, option B is incorrect.
C. 8 < 50 < 9
50 is greater than 8 but it is not less than 9, so, option C is incorrect.
D. 10 < 50 < 11
50 is greater than 10 but it is not less than 11, so, option D is incorrect.
Thus, none of the options is correct.