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Elena-2011 [213]
3 years ago
10

The roots of 3x^2+kx+12=0 are equal, find k.

Mathematics
2 answers:
Olin [163]3 years ago
5 0

Answer:

<em>k = 12</em>  

Step-by-step explanation:

3(x² + kx + 2²) = 3(x² + ____x + 4) = 3(x² + 4x + 4) = 3x² + 12x + 12 ⇒ <em>k = 12</em>

Xelga [282]3 years ago
4 0

Answer:

Step-by-step explanation:

3x^2+kx+12=0

k= -3x-12/x

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