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3 years ago

I really need help on this question please

Mathematics

2 answers:

ivanzaharov [21]3 years ago

8 0

H. 4,8,12,16 will be your answer (: hope this helps!

VMariaS [17]3 years ago

7 0

H is the correct answer

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An invoice for $450 has terms 2/10, 1/30, n/60. If you pay on the eighth day, how much will you remit? A. $446.00 B. $450.00 C.

elena-s [515]

I believe the answer is: C. $441.00

the terms 2/10, 1/30, n/60. indicates that you would get 2% discount if you pay within 10 days and 1% discount if you pay within 30 days.

If you pay on the 8th day, the amount of your payment would be:

$ 450 x 98% = $ 441

8 0

3 years ago

a certain forest covers an area of 4800km squared. if each year the area decreased by 6.75%what will be the area after 11 years

Sunny_sXe [5.5K]

Answer-

The area after 11 years will be 2225.28 km²

Solution-

This can be represented as exponential decreasing function,

$y=a(1 - r)^t$

Where,

a = starting amount
r = rate
t = years

Putting the values,

$y=4800(1-0.0675)^{11}$

$\ =4800(0.9325)^{11}$

$\ =4800\times 0.4636$

$\ =2225.28$

Therefore, at this rate the area of the forest after 11 years will be 2225.28 km².

5 0

3 years ago

Noah is solving the inequality 7x + 5 > 2x + 35. First, he solves the equation 7x + 5 = 2x +35 and gets x = 6. How does the s

Monica [59]

Answer:

1682

Step-by-step explanation:

because if you add or subtract or divide or times it it will some how show the answer and you will have to take the risk of it being right or nor

4 0

3 years ago

Read 2 more answers

The incubation period for the eggs of a House Wren has a normal probability distribution with a mean time of 336 hours and a sta

geniusboy [140]

Answer:

2.28%

Step-by-step explanation:

If X is the random variable that measures the time of incubation needed before hatching, we want

P(X>343)

This is the area under the normal curve whose mean is 336 hours and its standard deviation 3.5 hours to the right of the point 343. (See picture attached)

This can be done easily with the help of a computer and we find

P(X>343) = 0.0228 or 2.28%

6 0

3 years ago

Q.2. A cricketer scores the following runs in eight innings :

dangina [55]

Answer: Mean Score = 50 Range = 31

Step-by-step explanation:

58+76+40+35+46+45+0+100=400

400/8=50

Range = subtract smallest number from largest number

54 - 23 = 31

7 0

3 years ago