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Sati [7]
3 years ago
11

The width of a rectangle is the sum of the length and 1. The area of the rectangle is 20 units. What is the width, in units, of

the rectangle?
Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0

Answer:

W=5

Step-by-step explanation:

W=Width=Length + 1

L = Length

Area = Length * Width = 20

Area = L * W = L * (L+1) = 20

Distribute the L:   L^2 + L = 20

Subtract 20 from both sides: L^2 + L -20 = 20-20

Simplify:  L^2+L-20=0

Factor (L-4)(L+5)=0

Solve using the zero property: L-4=0, L=4      L+5=0, L=-5

The two options for length are 4 and -5. Only 4 will work for L since it cannot be negative.   Width is Length + 1 = 5

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A square 20 cm long and a rectangle 24 cm long have the same perimeter. Find the area of the rectangle.
Nitella [24]
20 * 4 = 80 = perimeter of the square 24*2 = 48, the length of two sides of the rectangle. Deducting from 80 we are left with 32 and dividing by 2 we know the rectangle is 24 x 16 Area = L * W, so you can calculate the area of the rectangle.
384
4 0
3 years ago
The measures of two angles of a triangle are 61 and 84 degrees. Find the measure of the third angle.
Serhud [2]

Answer:

The measure of the third angle is 35°.

Step-by-step explanation:

The sum of the three angles of a triangle is always 180°.

Let the measure of the third angle be x.

∴ 61° + 84° + x = 180°

           145 + x =180°

                    x = 180 - 145

                    x = 35°

Hope this answer was helpful!!

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8 0
3 years ago
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The sum of two numbers is 98. One number is 76 less than the other.
Lady bird [3.3K]

Answer:

Step-by-step explanation:

1. n + y = 98

2. n = 76 - t

7 0
3 years ago
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Use the slope formula to find the slope of the line that passes through the points (6,3) and (9,8).
Anni [7]
Correct answer is 5/3
8 0
3 years ago
Which number line represtents the solution to |x+4|=2?​
vlada-n [284]

Answer:

Points -2 and -6 on the number line are the two solutions.

Step-by-step explanation:

Use the definition of absolute value as a starting point

|x|=x\,\,\mbox{for}\,\,x\geq 0\\|x|=-x\,\,\mbox{for}\,\,x

To solve the equation, you need to treat the two cases as above:

|x+4|=x+4=2\,\,\,\mbox{for}\,\,x+4\geq 0\implies x\geq -4\\x+4=2\implies x=-2

The solution x=-2 is consistent with the condition x>=-4, so it is the first and valid solution. Now the second case of the absolute value:

|x+4|=-(x+4)=2\,\,\,\mbox{for}\,\,x+4< 0\implies x

Again, the second solution -6 complies with the requirement that x<-4, so it is valid.

7 0
3 years ago
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