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timurjin [86]
3 years ago
5

(-59)-(-18)/(+3)+(-2)(+4)+-27-(-3)

Mathematics
2 answers:
mojhsa [17]3 years ago
8 0
-41/25 I believe, I'm not sure why you put some addition signs in the inside of parentheses
g100num [7]3 years ago
8 0
-85 is the correct answer
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In the year 2000, the population of a city was 600,000 citizens. The population increases at a rate of 1.8% per year.
Alona [7]
Y=600000(1+1.8%)^(x-2000)
So the population in 2012
Y=600,000×(1+0.018)^(2,012−2,000)
Y=743,232
6 0
3 years ago
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Solve: 1 × -23 = Question 9 options: -1 1 23 -23
Nonamiya [84]

Answer:

-23

Step-by-step explanation:

  • 1 × -23

1. When multiply a positive number by a negative number, the answer will always be negative.

2. When we multiply any number by 1, that number will stay the same.

  • 1 * -23
  • -23

Therefore, the answer is -23!

8 0
2 years ago
40% of what number is 68?
MakcuM [25]
0.4 * x = 68
x = 68/0.4
x = 170

check:

0.4 * 170 = 68
6 0
3 years ago
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A perfect square is a number that has integer square root
Fiesta28 [93]

tr it and it wil; he;p

6 0
3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
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