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3 years ago

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The body length of a daddy long-legs spider is about 0.000002 kilometer. Which of the following is equivalent to the length of t

he spider in scientific notation?

1 answer:

lara31 [8.8K]3 years ago

8 0

Scientific notation: 2 x 10^-6

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Use a table of trigonometric values to find the angle θ in the right triangle in the following problem. Round to the nearest deg

Firdavs [7]

Heyyyyyy new friends and I have no clue what the answer is cause I don’t feel like reading that but anyway yea nfs?

4 0

3 years ago

The graph of a logarithmic function is shown below.

soldier1979 [14.2K]

Answer:

x > 0

Step-by-step explanation:

Domain of a function is defined by the set of x-values of the graph of a function.

From the graph attached,

x-values are starting from x > 0 [Since x ≠ 0] and moves towards infinity,

Therefore, domain of the function will be,

(0, ∞) Or x > 0

7 0

3 years ago

Read 2 more answers

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting. It is

yan [13]

Answer:

No, there is not sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting.

This means that the null hypothesis is:

$H_{0}: \mu = 434$

It is believed that the machine is underfilling the bags.

This means that the alternate hypothesis is:

$H_{a}: \mu < 434$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

434 is tested at the null hypothesis:

This means that $\mu = 434$

A 9 bag sample had a mean of 431 grams with a variance of 144.

This means that $X = 431, n = 9, \sigma = \sqrt{144} = 12$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{431 - 434}{\frac{12}{\sqrt{9}}}$

$z = -0.75$

P-value of the test:

The pvalue of the test is the pvalue of z = -0.75, which is 0.2266

0.2266 > 0.01, which means that there is not sufficient evidence to support the claim that the bags are underfilled.

7 0

3 years ago

What is a quadratic equation? And how do you solve them?

Allisa [31]

Answer:

A quadratic equation is some thing like

(x+2)^2

or

(x+2)(x+5)

In order to solve them, the most basic method is the FOIL method

F-First

O-Outside

I-Inner

L-Last

So for example

(x+2)^2

Which is basically

(x+2)(x+2)

So the first is the 2 Xs

(x+2)(x+2)

x*x=x^2

The outer is the x and the 2,

(x+2)(x+2)

2*x=2x

Now the Inner which is the 2 and the x

(x+2)(x+2)

2*x=2x

And finally the last which is the 2 and the second 2

(x+2)(x+2)

2*2=4

Now add them all up

X^2+2x+2x+4

Combine like terms

x^2+4x+4

There you have it

Do the same with every other quadratic equation

3 0

3 years ago

You are working for a company that designs boxes, bottles and other containers. You are currently working on a design for a milk

ra1l [238]

Volume is a measure of the <u>quantity </u>of <em>substance</em> a given <u>object</u> can contain. The required answers are:

1.1 The <u>volume</u> of each <u>milk</u> carton is 360 $cm^{3}$ .

1.2 The area of <em>cardboard</em> required to make a single <u>milk</u> carton is 332.6 $cm^{2}$ .

1.3 Each <u>carton</u> can hold 0.36 liters of <u>milk</u>.

1.4 The <em>cost</em> of filling the 200 <u>cartons</u> is R 86.40.

The <u>volume</u> of a given <u>shape</u> is the amount of <em>substance</em> that it can contain in a 3-dimensional <em>plane</em>. Examples of <u>shapes</u> with volume include cubes, cuboids, spheres, etc.

The <u>area</u> of a given <u>shape</u> is the amount of <em>space</em> that it would cover on a 2-dimensional <em>plane</em>. Examples of <u>shapes</u> to be considered when dealing with the area include triangle, square, rectangle, trapezium, etc.

The box to be considered in the question is a <u>cuboid</u>. So that;

<u>Volume</u> of <u>cuboid</u> = length x width x height

Thus,

1.1 The <u>volume</u> of each <u>milk</u> carton = length x width x height

= 6 x 6 x 10

= 360

The <u>volume</u> of each <u>milk</u> carton is 360 $cm^{3}$ .

1.2 The <em>total area</em> of<em> cardboard </em>required to make a single<u> milk</u> carton can be determined as follows:

i. <u>Area</u> of the <u>rectangular</u> surface = length x width

= 6 x 10

= 60

Total <u>area</u> of the <u>rectangular</u> surfaces = 4 x 60

= 240 $cm^{2}$

ii. <u>Area</u> of the <u>square</u> surface = side x side = s²

= 6 x 6

<u>Area</u> of the <u>square</u> surface = 36 $cm^{2}$

iii. There are four <em>semicircular</em> <u>surfaces</u>, this implies a total of 2 <u>circles</u>.

<em>Area</em> of a <u>circle</u> = $\pi r^{2}$

where r is the <u>radius</u> of the <u>circle</u>.

Total <u>area</u> of the <em>semicircular</em> surfaces = 2 $\pi r^{2}$

= 2 x $\frac{22}{7}$ x $(3)^{2}$

= 56.57

Total <u>area</u> of the <em>semicircular</em> surfaces = 56.6 $cm^{2}$

Therefore, total area of <em>cardboard</em> required = 240 + 36 + 56.6

= 332.6 $cm^{2}$

The <u>area</u> of <em>cardboard</em> required to make a single <em>milk carton</em> is 332.6 $cm^{2}$ .

1.3 Since,

1 $cm^{3}$ = 0.001 Liter

Then,

360 $cm^{3}$ = x

x = 360 x 0.001

= 0.36 Liters

Thus each<em> carton</em> can hold 0.36 liters of <u>milk</u>.

1.4 total cartons = 200

<em>Total volume</em> of <u>milk </u>required = 200 x 0.36

= 72 litres

But, 1 kiloliter costs R1 200. Thus

<em>Total volume</em> in kiloliters = $\frac{72}{1000}$

= 0.072 kiloliters

The <u>cost</u> of filling the 200 cartons = R1200 x 0.072

= R 86.40

The <u>cost</u> of filling the 200 <u>cartons</u> is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

#SPJ1

4 0

2 years ago