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Cloud [144]
4 years ago
15

Which number is the best approximation for

Mathematics
1 answer:
olga_2 [115]4 years ago
6 0
It should be C, I got 7.1.
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Simplify -2(-9x+3) Show work
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see attached image

Step-by-step explanation:

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10 rad 3 / 2

Step-by-step explanation:

x = missing angle of the full traingle

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Ahat [919]

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x > 1⅘

Step-by-step explanation:

(⅔)x - ⅕ > 1

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In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2. The numbers of
klio [65]

Answer:

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2

Three weeks, so \mu = 2*3 = 6

Calculate the probability that fewer than four tornadoes occur in a three-week period.

This is:

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.0025

P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.0149

P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.0446

P(X = 3) = \frac{e^{-6}*6^{3}}{(3)!} = 0.0892

Then

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0025 + 0.0149 + 0.0446 + 0.0892 = 0.1512

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

7 0
3 years ago
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