All categories

2 years ago

1. Find the volume of the object below.*

Mathematics

1 answer:

Alex787 [66]2 years ago

4 0

Answer:

228 cubic centimeters

Step-by-step explanation:

Find the volume for the blue box: 8 x 1 x 6 = 48

Find the volume of the orange box: 6 x 6 x 5 = 180

48 + 180 = 228

You might be interested in

When f(x)=4, what is th<br>0

tiny-mole [99]

Answer:

F(x)=4 means you plug in the 4 into where the variable is.

Step-by-step explanation:

Not really sure what your question meant but If you trying to find a problem with f(x)=4, then you plug in 4 into the variable of x.

3 0

2 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

Anthony purchased a T-shirt for $14.95 and a pair of pants for $21.35.

Mashutka [201]

Answer:

Anthony gave the sales clerk $40

Step-by-step explanation:

7 0

2 years ago

What is the answer to this question ?

nirvana33 [79]

Answer:

If you go to a website with a graph place the points and look where the line sets

Step-by-step explanation:

7 0

3 years ago

A line segment has an endpoint at (5,2) and has a negative slope. Which of the following points could be the other endpoint?

slavikrds [6]

<span>C. (4,3)

Draw and plot on a graph and (4,3) could be the other end point, which
x < 5
y > 2</span>

6 0

3 years ago