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Leno4ka [110]
3 years ago
8

Addison plays 1/8 of a song in 1/2 of a minute. How many minutes will he need to play a full song/

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

4 minutes

Step-by-step explanation:

1/2 minute times 8 eights of a song = 4 minutes

Ierofanga [76]3 years ago
3 0

Answer:

4 minutes

Step-by-step explanation:

if 1/8 of a song is 1/2 of a minute you would multiply 1/2 by 8

1/2 times 8/1 equals 8/2

8/2 equals 4

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katrin [286]
The operation of this problem is B multiplication
6 0
3 years ago
Find the slope of the linear function graphed below.<br> A. m=-4/3 B. m=4/3 C. m=3/4 D. m=-3/4
vodka [1.7K]

Answer:

0

Step-by-step explanation:

use the slope formula <u>y^2-y^1</u>

                                     x^2-x^1

8 0
3 years ago
Please help thank you
Cerrena [4.2K]

Answer:

the first one maybe?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Verify that the conclusion of Clairaut’s Theorem holds, that is, uxy = uyx, u=tan(2x+3y)
choli [55]

Answer: Hello mate!

Clairaut’s Theorem says that if you have a function f(x,y) that have defined and continuous second partial derivates in (ai, bj) ∈ A

for all the elements in A, the, for all the elements on A you get:

\frac{d^{2}f }{dxdy}(ai,bj) = \frac{d^{2}f }{dydx}(ai,bj)

This says that is the same taking first a partial derivate with respect to x and then a partial derivate with respect to y, that taking first the partial derivate with respect to y and after that the one with respect to x.

Now our function is u(x,y) = tan (2x + 3y), and want to verify the theorem for this, so lets see the partial derivates of u. For the derivates you could use tables, for example, using that:

\frac{d(tan(x))}{dx} = 1/cos(x)^{2} = sec(x)^{2}

\frac{du}{dx}  =  \frac{2}{cos^{2}(2x + 3y)} = 2sec(2x + 3y)^{2}

and now lets derivate this with respect to y.

using that \frac{d(sec(x))}{dx}= sec(x)*tan(x)

\frac{du}{dxdy} = \frac{d(2*sec(2x + 3y)^{2} )}{dy}  = 2*2sec(2x + 3y)*sec(2x + 3y)*tan(2x + 3y)*3 = 12sec(2x + 3y)^{2}tan(2x + 3y)

Now if we first derivate by y, we get:

\frac{du}{dy}  =  \frac{3}{cos^{2}(2x + 3y)} = 3sec(2x + 3y)^{2}

and now we derivate by x:

\frac{du}{dydx} = \frac{d(3*sec(2x + 3y)^{2} )}{dy}  = 3*2sec(2x + 3y)*sec(2x + 3y)*tan(2x + 3y)*2 = 12sec(2x + 3y)^{2}tan(2x + 3y)

the mixed partial derivates are equal :)

7 0
3 years ago
Which expression is not equivalent to 6^3/6^6?<br><br> a: 1/6^2<br><br> or<br><br> b: 1/6^3
Angelina_Jolie [31]

Answer:

<h2>A. 1/6^2</h2>

Step-by-step explanation:

6^3/6^6 = 1/216

1/6^2 = 1/36 ≠ 1/216

1/6^3 = 1/216

7 0
4 years ago
Read 2 more answers
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