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dybincka [34]
3 years ago
12

Simplify. Remove all perfect squares from inside the square root.

"TexFormula1" title="\sqrt{63}" alt="\sqrt{63}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

3 \sqrt{7}

Step-by-step explanation:

1) Rewrite 63 as its prime factors.

\sqrt{3 \times 3 \times 7}

2) Group the same prime factors into pairs.

\sqrt{(3 \times 3) \times 7}

3) Rewrite each pair in exponent form.

\sqrt{ {3}^{2} \times 7 }

3) Use this rule

\sqrt{ {x}^{2} }  = x

3 \sqrt{7}

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NeTakaya
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malfutka [58]

For this case we have that by definition, the area of a triangle is given by:

A = \frac {b * h} {2}

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b = 6 + 2h

Substituting we have:

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We factor by looking for two numbers that, when multiplied, are obtained -88 and when added together, +3 is obtained.

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Answer:

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