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dybincka [34]
3 years ago
12

Simplify. Remove all perfect squares from inside the square root.

"TexFormula1" title="\sqrt{63}" alt="\sqrt{63}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

3 \sqrt{7}

Step-by-step explanation:

1) Rewrite 63 as its prime factors.

\sqrt{3 \times 3 \times 7}

2) Group the same prime factors into pairs.

\sqrt{(3 \times 3) \times 7}

3) Rewrite each pair in exponent form.

\sqrt{ {3}^{2} \times 7 }

3) Use this rule

\sqrt{ {x}^{2} }  = x

3 \sqrt{7}

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If Lylah completes the square for f(x)=x^2-12x+7 in order to find the minimum, she must write f(x) in the general form f(x)=(x-a
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Next, half the coefficient of second term in the parenthesis (12x) and square the result. Make sure to subtract outside the parenthesis what you added inside so that the equation stays equal.

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