For this case we first write the equation of which we will use:
I (db) = 10log (l / l)
We substitute the value of l.
We have then:
l = 10 ^ 8lo
Substituting in the given equation:
I (db) = 10log ((10 ^ 8lo) / lo)
Rewriting:
I (db) = 10 * log (10 ^ 8)
I (db) = 80
Answer:
I (db) = 80
option 4
Answer:
y = -x-3
x-y = -3
x - 2y = 10
Step-by-step explanation:
x − 3y = 6
Slope intercept form is y = mx +b
We need to solve for y
Subtract x from each side
x-x-3y = -x+6
-3y = -x +6
Divide each side by -3
-3y/-3 = -x/-3 +6/-3
y = 1/3 x -2
Standard form is Ax +By = C
y = -x-3
Add x to each side
x-y = -x+x-3
x-y = -3
y = 1/2x -5
We do not like fractions in standard form, so multiply by 2
2y = 2*1/2x -2*5
2y =x-10
Subtract x from each side
-x +2y = x-x-10
-x+2y = -10
We like to have the coefficient on x be positive
Multiply by -1
x - 2y = 10
Answer: y = 4x + 5/4
Step-by-step explanation: Plug in the slope and y-intercept into the equation y = mx + b, where m is the slope and b is the y-intercept, and such that m, b ≠ 0.
Answer:
x=1
You solve for x by cross multyplying
Answer:
see below
Step-by-step explanation:
Since RT bisects QRS
1/2 QRS = TRS
1/2 ( 9x+214) = -9x+53
Multiply each side by 2
9x +214 = -18x+ 106
Add 18x from each side
9x +214+18x = 106
27x +214 = 106
Subtract 214 from each side
27x = 106-214
27x =-108
Divide by 27
27x/27 = -108/27
x = -4
TRS = -9x+53
=-9 *-4 +53
= 36+ 53
=89