This is an example of conditional probability because we are trying to find the probability of an event occurring GIVEN the occurrence of some other event. There is a formula for this (see image attached).
If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.
Answer:
acute and obtuse
Step-by-step explanation:
the acute is less than 90 degrees and obtuse is more than 90 degrees
Answer:
7/10 = 63/90
4/9 = 40/90
Step-by-step explanation:
Rewriting input as fractions if necessary:
7/10, 4/9
For the denominators (10, 9) the least common multiple (LCM) is 90.
LCM(10, 9)
Therefore, the least common denominator (LCD) is 90.
Calculations to rewrite the original inputs as equivalent fractions with the LCD:
7/10 = 7/10 × 9/9 = 63/90
4/9 = 4/9 × 10/10 = 40/90
The answer is 2100. Round to the nearest hundred for each number and add.
2/11 of 264 books would be 48 books