5x+34=-2(1-7x)
Steps:
5x+34=-2+14x
5x+34-14x= -2
-9x + 34= -2
-9x = -2-34
-9x = -36
X= -36/-9
Answer: x= 4
This may not be very pretty.
(2x + 5) * (2x + 5) expanded is (use foil)
F = 4x^2
O = 2x * 5 = 10x
I = 2x + 5 = 10x
L = 25
Total = 4x^2 + 20x + 25
(x + 3)(x + 3) = x^2 + 6x + 9 by the same method
(2x + 7)(2x + 7) = 4x^2 + 28x + 49 Same method.
4x^2 + 20x + 25 + x^2 + 6x + 9 = 4x^2 + 28x + 49
5x^2 + 26x + 34 = 4x^2 + 28x + 49 Collect everything on the left.
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
x + 3 will have no meaning.
x - 5 = 0
x = 5
2x + 5 = 2*5 + 5 = 15
x + 3 = 5 + 3 = 8
2x+ 7 = 2*5 +7 = 17
Check
15^2 + 8^2 = 17^2
225 + 64 = ? 289
289 = 289
a = 15 <<<<< answer
b = 8 <<<<< answer
c = 17 <<<<< answer
https://www.mesacc.edu/~scotz47781/mat120/notes/quad_formula/quad_formula.html
Use this link to help you .
We know that
[volume of the ramp]=[area of the base]*height
area of the base=37.4 yd²
height=5 yd
so
[volume of the ramp]=[37.4]*5----> 187 yd³
the answer is
the volume of the ramp is 187 yd³
M=3
You would begin by cross multiplying and then solving it from there:
5(m-3)=4(m-3)
5m-15=4m-12
5m-4m=-12+15
m=3
