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FromTheMoon [43]
3 years ago
5

- The Fun Guys game rental store charges an annual fee of $5 plus $5.50 per game rented. The Game Bank charges an annual fee of

$17 plus $2.50 per game rented.
Write an equation in y=mx+b form describing the total cost to rent x games at each store.
Fun Guys:
Game Bank: ​
Mathematics
1 answer:
Elena L [17]3 years ago
4 0
Fun guys: 5.50x + 5
Game Bank: 2.50x + 17
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Anika is 7 years older than Kit. If Kit is k years old, how old is Anika?
zaharov [31]

Answer:

k+7

Step-by-step explanation:

because k is the age of kit so Anika is 7 years older, so u have to add

sorry if I'm wrong

7 0
3 years ago
Given the triangle below is m <br> A. 68.6<br> B. 82.8<br> C. 74.4<br> D. 80.6
erastova [34]

Answer:

B. 82.8

Step-by-step explanation:

5 0
3 years ago
The square based pyramid is cut horizontally at a height of 15cm to leave this frustum. Calulate the volume of the frustum.
allsm [11]

Answer:

The answer is given below

Step-by-step explanation:

The question is not complete. The correct question is:

A square based pyramid have a height of 30 cm and base of 10 cm. The The square based pyramid is cut horizontally at a height of 15cm to leave this frustum.

Answer:

The frustum would have a base of 10 cm and height of 15 cm. The lower base has a length of 10 cm. to calculate the upper base, we use the formula:

\frac{height\ of\ frustum}{height\ of \ pyramid}=\frac{base \of\ upper\ edge}{base \of\ lower\ edge}

Substituting:

\frac{30}{15}=\frac{10}{b} \\ b=15*10/30=5

The volume of the frustum is given by the formula:

V=\frac{h}{3}(A_1+A_2+\sqrt{A_1A_2} )

Where h is the height of the frustum = 15 cm, A1 is the area of the lower base = 10 * 10 = 100 cm², A1 is the area of the upper base = 5 * 5 = 25 cm²

Substituting gives:

V=\frac{h}{3}(A_1+A_2+\sqrt{A_1A_2} )=\frac{15}{3}(100+25+\sqrt{100*25} )= 875\ cm^3

7 0
3 years ago
My Notes OAsk Your Tea The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t an
Papessa [141]

Answer:

10.96 hours will take for 85% of the lead to decay.

Step-by-step explanation:

Suppose A represents the amount of Pb-209 at time t,

According to the question,

\frac{dA}{dt}\propto A

\implies \frac{dA}{dt}=kA

\int \frac{dA}{A}=\int kdt

ln|A|=kt+C_1

A=e^{kt+C_1}

A=e^{C_1} e^{kt}

\implies A=C e^{kt}

Let A_0 be the initial amount,

A_0=C e^{0} = C

\implies A=A_0 e^{kt}

Since, the half-life of 3.3 hours.

\implies \frac{A_0}{2}=A_0 e^{3.3k}\implies e^{3.3k}=0.5\implies k=-0.21004

\implies A=A_0 e^{-0.21004t}

Here, A_0=1\text{ gram}

A=(100-85)\% \text{ of }A_0=15\%\text{ of }A_0=0.15A_0

By substituting the values,

0.15A_0=A_0 e^{-0.21004t}

0.15=e^{-0.21004t}

\implies t\approx 10.96\text{ hour}

6 0
3 years ago
What is 5×7 to the fourth power 5×7 to the second power in standard form
lapo4ka [179]
35^6 power. This is a simple problem just add the exponents! Hope this helps!

5 0
3 years ago
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