SA=2(LW+LH+WH)
SA=94
L=3
W=4
94=2(3*4+3H+4H)
divide both sides by 2
47=3*4+3H+4H
47=12+7H
minus 12 both sides
35=7H
divide oth sides by 7
5=H
5m
Let x be the unknown number
2x +7 = 39
2x+7-7 = 39-7
2x = 32
2x/2 = 32/2
x=16
You use the balance method to solve. First, you cancel the +7 by subtracting the 7 ON BOTH SIDES to balance the equation.. After that, you are left with 2x, where you will need to isolate the x by dividing by 2 ON BOTH SIDES to balance it.
Hope this helps
Answer: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!
Step-by-step explanation: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!
So if the bag contains half as many red marbles as blue ones, and there are 8 reds then there are 16 blues. 16 + 8= 24 if you want there to be 1/4 white marbles add 6. 6/30 is 1/4.
So the answer comes out to be 30 marbles in the bag
