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shtirl [24]
3 years ago
13

Find the slope of a line perpendicular to 4x-y=6

Mathematics
1 answer:
ratelena [41]3 years ago
8 0

Answer:

The slope is -1/4

Step-by-step explanation:

perpendicular line is y=-\frac{1}{4}x-6

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What are the intercepts of f(x)=x^2
dusya [7]
C. It is a basic parabola

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Use the spinner to identify the probability to the nearest hundredth of the pointer landing on a non-shaded area. HELP PLEASE!!
Tatiana [17]

the correct answer should be:

1. 0.56

2. 0.31

8 0
3 years ago
Proofs and congruent triangles ( serious full answers only or 1 star and report )
krok68 [10]

Answer:

<em>There are 5 ways to find if two triangles are congruent.</em>

<em>SSS-</em><em> {Side Side Side Congruence.}</em>

<em>This law of congruence states that if we have two triangles, each with the same measures on each 3 sides it deems the triangles congruent.</em>

<em>SAS- </em><em>{Side Angle Side Congruence.}</em>

<em>This law of congruence states that if we have two triangles, with 2 equal sides and one angle which is common among them; the triangles are congruent.</em>

<em>ASA- </em><em>{Angle Side Angle Congruence.}</em>

<em>This law of congruence states that if we have two triangles, with 2 congruent angle measures and 1 congruent side; the triangles are indeed congruent.</em>

<em>AAS- </em><em>{Angle Angle Side Congruence.}</em>

<em>You may be wondering how this law of congruence differs from the previous one. </em><em> ASA </em><em>refers to any two angles and the included side, whereas </em><em>AAS </em><em>refers to the two corresponding angles and the non-included side.</em>

<em>HL- </em><em>{Hypotenuse Leg Congruence.}</em>

<em>This law of congruence states that if we have two triangles, with a common (congruent) leg and hypotenuse; the triangles are congruent.</em>

<em />

<em>I really hoped this helped, if it didn't leave a comment I am always open to feedback. If it did let me know, brainiest is always appreciated! </em>

<em>Hope you have a great rest of your day.</em>

3 0
1 year ago
Read 2 more answers
An open rectangular box with square base has a volume of 256 cubic inches. determine the equation for the volume and surface are
Serjik [45]
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box

we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1

surface area of the box=area of the base+perimeter of base*height

area of the base=b²
perimeter of the base=4*b

surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2

substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b

the answer is

the formula of the volume of the box is  V=b²*h-----> 256=b²*h

the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
4 0
3 years ago
Whats 16 = k/11<br>and v/8=2
Dvinal [7]
16= \frac{k}{11} &#10;\\16*11=k&#10;\\k=176&#10;&#10;

\frac{v}{8} =2&#10;\\v=8*2&#10;\\v=16
6 0
3 years ago
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