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horsena [70]
3 years ago
15

Sorry again but i'm having trouble on this one

Mathematics
1 answer:
Lisa [10]3 years ago
5 0

Answer:

m∠PNO = 60°

m∠O = 33°

Step-by-step explanation:

∡NPO is 87° because it's a vertical angle with the 87° angle

3) ∡PNO is supplementary to the 120° angle (they must add to 180°)

4) m∠O = 180 - (60 + 87) = 33

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Find 5% of $43.79. $218.95 $2.19 $21.90 $2,189.50
ddd [48]
<span>43.79      *0.05= </span>2.1895
218.95    *0.05= 10.9475
2.19        *0.05= 0.1095
21.90      *0.05= 1.095
2,189.50 *0.05= <span>109.475
</span>
hope this helps
8 0
3 years ago
A multiple must be greater than or equal to the largest starting number. True or False
podryga [215]

I'll use multiples of 2 and 4 as an example:

Multiples of 2: 2, 4, 6, 8...

Multiples of 4: 4, 8, 12, 16...

The least common multiple in this case is 4. The LCM is always ≥ the largest starting number, which is 4 for this example. Therefore, the statement is true.

<em>Hope this helps! :)</em>

8 0
3 years ago
Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at
sweet [91]

Answer:  The answer is 35 minutes.


Step-by-step explanation:  Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

In 9 minutes, distance run by Gavin = 1 mile.

So, in 1 minute, distance travelled by Gavin will be

d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.

Now, difference between Lars and Gavin's rate of runnings is

\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.

Therefore, the time taken by Lars to reach Gavin is given by

t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.

Thus, the required time is 365 minutes.  


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Goryan [66]
It would be 3.05 feet tall
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(30 POINTS!!!) Suppose △ABC≅△LMN .
Mandarinka [93]
The correct answer would be the first and the last ones.
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