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horsena [70]
2 years ago
15

Sorry again but i'm having trouble on this one

Mathematics
1 answer:
Lisa [10]2 years ago
5 0

Answer:

m∠PNO = 60°

m∠O = 33°

Step-by-step explanation:

∡NPO is 87° because it's a vertical angle with the 87° angle

3) ∡PNO is supplementary to the 120° angle (they must add to 180°)

4) m∠O = 180 - (60 + 87) = 33

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If you had to pick a number 1-4 what would be the luckiest?
earnstyle [38]

I always feel drawn to the number 2 for some reason because it is in the middle between 2 and four and usually when given an option to pick a number I never pick a number that they say. Personally I just feel drawn to pick the number 2 its a nice even number and perhaps could be lucky :)

3 0
2 years ago
Two balls are drawn in turn without replacement from a box containing three green and two white balls.Find the probability of dr
AURORKA [14]

Answer:

A. 2/5

B.2/5

C. 3/5

D. 5/5=1

7 0
3 years ago
a 10 ft ladder leans against a wall with its foot braced 3ft. from wall's base how far up the wall does the ladder resach
geniusboy [140]
Ladder makes a right triangle with the wall and ground. The hypotenuse = length of the ladder = 10 ft 
Let the height be h
By Pythagorean theorem 
10^2 = 3^2 + h^2 
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6 0
3 years ago
Can someone give me the answer
EleoNora [17]

Answer:

4

Step-by-step explanation:

6 0
2 years ago
preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha
VladimirAG [237]

Answer:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

n=369

Step-by-step explanation:

1) Notation and definitions

X=40 number of the selected labourers opt for a new incentive scheme.

n=100 random sample taken

\hat p=\frac{40}{100}=0.4 estimated proportion of the selected labourers opt for a new incentive scheme.

p true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

And rounded up we have that n=369

8 0
3 years ago
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