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2 years ago

Rewrite the equation as y-2=-2/3(x-(-1)) to identify a point on the graph

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

7 0

Answer:

point (-1, 2)

Step-by-step explanation:

Your equation is shown here in point-slope form, so a point on the graph can be read from the given equation. (No further rewrite is necesary.)

The point-slope form is ...

y -k = m(x -h)

Comparing this to your given equation ...

y -2 = (-2/3)(x -(-1))

we see that ...

k = 2, m = -2/3, h = -1

The point on the graph is (h, k) = (-1, 2).

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2 years ago

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1 year ago

find the area and the circumference of a circle with radius 5yd. use the value 3.14 for like, and don’t round your answer to the

Zanzabum

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Step-by-step explanation:

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2 years ago

Read 2 more answers

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So the volume V of prism with length $1 \frac{1}{4}$ yards, width $2 \frac{1}{2}$ yards and height of 4 yards will be:

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3 years ago

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Step-by-step explanation:

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