angle AOB = 132 and is also the sum of angles AOD and
DOB. Hence
angle AOD + angle DOB = 132° ---> 1
angle COD = 141 and is also the sum of angles COB and BOD. Hence
angle COB + angle DOB = 141° ---> 2
Now we add the left sides together and the right sides of equations 1 and 2
together to form a new equation.
angle AOD + angle DOB + angle COB + angle DOB = 132 + 141 ---> 3
We should also note that:
angle AOD + angle DOB + angle COB = 180°
Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180
and solving for angle DOB:
180 + angle DOB = 132 + 141
angle DOB = 273 - 180 = 93°
Since there is a right angle, you can use Pythagoras' Theorem:
So x = √(24² + 7²) = 25
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Answer:
25
Answer:
35+28=63
Step-by-step explanation:
hope this helps
Answer:
6
Step-by-step explanation:
- 6x +5 = 0
- 6x + 9 -9 +5 = 0
[ - 6x + 9] - 4 =0
-4 = 0
= 4
(x-3) = 
or (x-3) = -
(x-3) = 2 or (x-3) = -2
x = 5 or x = 1
therefore, sum of these solutions is 5+1 = 6
1. Alternate exterior angles
So, C
2.
180 = 76 + 2x
104 = 2x
52 = x
So, B
4.
4a. No
4b. Yes
4c. No
4d. Yes
5.
180 = 35 + 35 + 2x
180 = 70 + 2x
110 = 2x
55 = x
So, C.
7.
12/8 = 30/y
Cross multiply
12y = 240
y = 20
So, C
8. Alternate interior angles
So, A
9.
A C and D
