Let the width = X
The length would be X + 20
Area = Length x width:
2400 = x * (x+20)
Simplify:
2400 = x^2 + 20x
Subtract 2400 from both sides:
x^2 + 20x - 2400 = 0
Factor:
(x-40) (x+60) = 0
Solve for both x's:
x = 40 and x = -60
The dimensions of a parking lot have to be positive values so you would use x = 40.
The width = x = 40
The length = x +20 = 40+20 = 60
The dimension of the parking lot is 40H x 60H
Answer:
a8 = 0.004
Step-by-step explanation:
Q is abt a geometric series given by the eqn: an = a1*r^(n-1)
given a1 = 40000, r = 0.1
an = 40000*(0.1)^(n-1)
a8 = 40000*(0.1)^(8-1)
= 40000*(0.1)^7
= 0.004
Answer:
h = 19.7 ft.
Step-by-step explanation:
Use the Pythagoras Theorem
Now we take square root on both sides,
so the value of h equals 19.7 ft.
11x2=22
22x6=132
I believe the answer is 132
