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mestny [16]
2 years ago
11

Help I will be marking brainliest!!!

Mathematics
1 answer:
guajiro [1.7K]2 years ago
3 0
<h3>AG = 27 and VA = 24. What is TO? </h3>

A. 45

B. 43

<h3>C. 36</h3>

D. 90

#CarryOnLearning.

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Solve the Expression<br> 5-(2*8)+14=
evablogger [386]

Answer:

3

Step-by-step explanation:

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GOOD MORNING! \(:0:)/
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Answer:

Good morning.

Step-by-step explanation:

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8 0
2 years ago
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Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic
Andrei [34K]

Answer:

\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

(x-a)^2+(y-b)^2+(z-c)^2=r^2

Where (x,y,z) are the points on sphere.

(a, b, c) is the center of the sphere and

r is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

Here,

x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2  =2 \\z_2 =3

So, Radius is:

r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}

Therefore the equation of the sphere is:

(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

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Using all or some of the digits 2, 3, 4 and 5, Edward writes
Vesnalui [34]

Using the arrangements formula, considering the given digits, it is found that Edward writes 6 numbers.

<h3>What is the arrangements formula?</h3>

The number of possible arrangements of n elements is given by the factorial of n, that is:

A_n = n!

In this problem, the first digit has to be 5, while the other three are arranged, hence the total number of arrangements is given by:

A_3 = 3! = 6

More can be learned about the arrangements formula at brainly.com/question/25925367

#SPJ1

5 0
1 year ago
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