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Kryger [21]
2 years ago
11

I need help it’s geometry

Mathematics
2 answers:
Genrish500 [490]2 years ago
6 0

Answer:

666666666666666666666666

sukhopar [10]2 years ago
4 0

Answer:8(x+15)

Step-by-step explanation:

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in a town, 11 000 people out of the total population of 50 000 are aged under 18. What percentage of the population is aged unde
Katen [24]

Answer:

22%

Step-by-step explanation:

1- 11000/50000 = 0.22

2- 0.22 x 100 = 22%

.. ..

8 0
3 years ago
Michael has 1.85 in dimes and nickels.He has a total of 25 coins.how many of each does he have
creativ13 [48]
D+n=25 subtract d from both sides *(if your wondering what d and n are it stands for Dimes and Nickels)* n=25-d   
0.10d+0.05= 1.85
0.10d+0.05(25-d)= 1.85
0.10d+1.25-0.05d= 1.85
0.05d = 0.60
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
My answer: He has 12 dimes (d=12) and 25-12=13 so 13 nickels.. Hope this helps! :)

5 0
3 years ago
The area of a circle is 81 ft 2 . What is the π circumference? Leave in terms of Pi.
KonstantinChe [14]

Answer:

10.2π

Step-by-step explanation:

Given data

Area of circle=  81 ft^2

Also, the expression for the area of a circle is

A=πr^2

substitute

81=3.142*r^2

r^2= 81/3.142

r^2= 25.77

square both sides

r= √25.77

r= 5.1

Also, the expression for the circumference is

C= 2πr

substitute

C= 2*π*5.1

C= 10.2π

Hence the circumference is 10.2π

7 0
3 years ago
Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t
Kobotan [32]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

here:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Therefore;

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

3 0
2 years ago
Good morning everyone :)​
Triss [41]

Answer:

Good Morning

:)

Step-by-step explanation:

5 0
2 years ago
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