How do I find the equation of a line in slope intercept form

Mathematics

1 answer:

Harman [31]2 years ago

7 0

Answer:

if ibunderstand you right....the type is y=ax+b

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Square root of 15-x=-3+Square root of 2x+3 Solve for x

PSYCHO15rus [73]

$
\sqrt{15-x}=-3\sqrt{2x+3}\impliedby \textit{divide by -3}
\\ \quad \\
\cfrac{\sqrt{15-x}}{-3}=\sqrt{2x+3}\impliedby \textit{squares both sides}
\\ \quad \\
\left( \cfrac{\sqrt{15-x}}{-3} \right)^2=(\sqrt{2x+3})^2\implies 
\cfrac{(\sqrt{15-x})^2}{(-3)^2}=(\sqrt{2x+3})^2
\\ \quad \\
\cfrac{15-x}{9}=2x+3\impliedby \textit{multiply both sides by 9}
\\ \quad \\
15-x=18x+27\impliedby \textit{solve for "x"}$

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3 years ago

Mariana averaged 80 on her first three math exams. The first score was 86. The second score was 74. What was the third exam scor

Anna71 [15]

The three scores are 86, 74, and an unknown score x. The average (i.e. the sum divided by how many there are) is 80, so we have

$\dfrac{86+74+x}{3}=80$

Multiply both sides by 3 and you get

$160+x=240$

Subtract 160 from both sides to get

$x=240-160=80$

Note: you could solve this exercise very quickly if you notice that the two numbers, 86 and 74, are symmetrical with respect to 80, which is the average. So, the third number must be the average.

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2 years ago

A large patio brick weighs 4 3/8 pounds. A small patio brick weighs 2 1/3 pounds. How much more does the large brick weigh?

Nikolay [14]

Subtracting the weight of the smaller brick from the larger gives us the weight difference:

4 3/8 lb - 2 1/3 lb. The two denominators are 8 and 3 respectively, resulting in an LCD of 24. Thus, our problem becomes:

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Answer: