What is the difference of 2x²y⁴− 7x²y⁴ ?

A. x<br> B. x^6<br> C. x^9<br> D. x^4

ivanzaharov [21]

Answer:

b

Step-by-step explanation:

6 0

3 years ago

Mr. Keller bought a car for $20,000. A study shows that a car will depreciate (go DOWN in value) by 15% each year. How much is M

Aneli [31]

Average annual value lost: $7,390.65First-year depreciation: $3,000.00Total depreciation: $11,125.89Total depreciation percentage: 55.63%Value of vehicle at end of ownership period: $8,874.11
see attachment for graph

7 0

4 years ago

For a polynomial P(x), the quotient P(x)/(x-2) has a remainder of 12. What is the value of P(2)? Please explain. Thanks :)

RoseWind [281]

Answer:

12

Step-by-step explanation:

P(x) has infinitely many solutions, but I am going to find the easiest one, which would be a linear equation.

First, notice that x-2 perfectly divides into itself.

Then, if you add 12 to x-2, you will end up with a remainder of 12. Therefore, P(x) would be x-2+12 = x+10.

Now that we know P(x), we can directly plugin 2 to find out P(2):

2+10 = 12

Therefore, P(2) = 12.

4 0

4 years ago

Can y'all please help me thanks u

mihalych1998 [28]

15. A is the answer because you need to divide the top by the bottom
16.B

3 0

3 years ago

Read 2 more answers

A sample of 25 commuters in the Washington, D.C., area yielded the sample mean commute time of 27.97 minutes and sample standard

xxMikexx [17]

Answer:

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes. The interpretation is that we are 99% sure that the true mean ommute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575*\frac{10.04}{\sqrt{25}} = 5.1706$

The lower end of the interval is the mean subtracted by M. So it is 27.97 - 5.1706 = 22.7994 minutes

The upper end of the interval is the mean added to M. So it is 6.4 + 0.3944 = 33.1406 minutes.

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes. The interpretation is that we are 99% sure that the true mean ommute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes.

5 0

4 years ago