5% Of 42,450 (.05*42,450=2,122.5)
2,122.5+42,450=44,572.5
4% of 44,572.5 (.04*44,572.5=1,782.9)
1,782.9+44,572.5=46,355.4
The answer is 46,355.4 miles
$10 (Teacher will purchase supplies) ... (2) bottles Elmer's Washable. Glue. (2) Elmer's Glue Sticks. (1) Expo Dry Erase marker ... 1 pk Crayola markers ... ALL, ITEMS will become ... pencil box (approx. size 5x8) ... 2 boxes of disinfectant wipes. Kindergarten - Ms. Amanda Hamilton ... Grades 3, 4, 5 - Mrs. Carol Drummond ... sticks 4 pocket folders with tabs-1 of each color (no designs) ... 1 glue stick. Art Box Ruler Colored pencils & sharpener 24 pack of crayons ... All inquiries will be responded to in a timely manner, and inquiries will be replied to via e-mail unless ...
First, a bit of housekeeping:
<span>The meaning of four consecutive even numbers is 15. Wouldn't that be "mean," not meaning? Very different concepts!
The greatest of these numbers is _______ a^1
"a^1" means "a to the first power. There are no powers in this problem statement. Perhaps you meant just "a" or "a_1" or a(1).
The least of these numbers is ______a^2.
No powers in this problem statement. Perhaps you meant a_2 or a(2)
In this problem you have four numbers. All are even, and there's a spacing of 2 units between each pair of numbers (consecutive even).
The mean, or arithmetic average, of these numbers is (a+b+c+d) / 4, where a, b, c and d represent the four consecutive even numbers. Here this mean is 15. The mean is most likely positioned between b anc c.
So here's what we have: a+b+c+d
------------- = 15
4
This is equivalent to a+b+c+d = 60.
Since the numbers a, b, c and d are consecutive even integers, let's try this:
a + (a+2) + (a+4) + (a+6) = 60. Then 4a+2+4+6=60, or 4a = 48, or a=12.
Then a=12, b=14, c=16 and d=18. Note how (12+14+16+18) / 4 = 15, which is the given mean.
We could also type, "a(1)=12, a(2)=14, a(3) = 16, and a(4) = 18.
</span>
Answer:
0.2916, 0.1488, 0.0319
Step-by-step explanation:
Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.
Since each trial is independent there is a constant probability for any random car to need oil is 0.10
Let X be the number of cars that need oil
A) Here X is BIN(4,0.1)
B) Here X is Bin (8, 0.1)
C) Here X is Bin (20,5)
