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Sedbober [7]
3 years ago
7

WILL GET BRANLIEST

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

The correct options are;

Answer to A1 is D

Answer to A2 is D

Answer to A3 is D

Answer to A4 is D

Answer to A5 is D

Answer to A6 is D

Answer to A7 is D

Answer to A8 is D

Answer to A9 is D

Answer to B1 is I

Answer to B2 is I

Answer to B3 is I

Answer to B4 is I

Answer to B5 is I

Answer to B6 is I

Step-by-step explanation:

The given function is f(x) = 9·x² + 54·x - 66

The extremum of the function are found as follows;

d(f(x))/dx = 0 = d(9·x² + 54·x - 66)/dx = 18·x + 54

∴ 18·x + 54 = 0 at the maximum or minimum points

x = -54/18 = -3

Given that d²(f(x))/dx² = 18 > 0. x = -3 is a minimum point

Given that the function is a quadratic function, we have;

1) Points to the left of x = -3 are decreasing

2) Points to the right of x = -3 are increasing.

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7 0
3 years ago
3x + ky = 8
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Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
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