All categories

3 years ago

WILL GET BRANLIEST

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

6 0

Answer:

The correct options are;

Answer to A1 is D

Answer to A2 is D

Answer to A3 is D

Answer to A4 is D

Answer to A5 is D

Answer to A6 is D

Answer to A7 is D

Answer to A8 is D

Answer to A9 is D

Answer to B1 is I

Answer to B2 is I

Answer to B3 is I

Answer to B4 is I

Answer to B5 is I

Answer to B6 is I

Step-by-step explanation:

The given function is f(x) = 9·x² + 54·x - 66

The extremum of the function are found as follows;

d(f(x))/dx = 0 = d(9·x² + 54·x - 66)/dx = 18·x + 54

∴ 18·x + 54 = 0 at the maximum or minimum points

x = -54/18 = -3

Given that d²(f(x))/dx² = 18 > 0. x = -3 is a minimum point

Given that the function is a quadratic function, we have;

1) Points to the left of x = -3 are decreasing

2) Points to the right of x = -3 are increasing.

You might be interested in

Linda knitted 1/6 of a sweater on Friday and 2/9 of the sweater on Saturday. On Sunday she knitted 1/2 of the remaining sweater.

sladkih [1.3K]

This is pretty simple. All you have to do is make the first and second fraction share a denominator by multiplying them by each other.

6 • 9 = 54

Then multiply each numerator by the opposing denominator.

1 • 9 = 9

2 • 6 = 12

Here are the new fractions:

9/54

12/54

Now add the 9 and 12 together.

9 + 12 = 21

The complete fraction:

21/54

Subtract 21 from 54 so you can get the remainder of the sweater.

54 - 21 = 33

This is the remainder fraction:

33/54

Can you simplify this? Yes, of course! They can both be divided by 3!

11/18

That is the remainder of the sweater. But you still have to divide it in half! After all, Linda only knitted half of the remaining sweater. Dividing it in half can be done just by multiplying the denominator by 2.

11/36

That should be your answer! Apologies if I got something wrong.

7 0

3 years ago

HELPPPPPPP!!!! 0÷0 Find the RATIO and the EXACT VALUE of the given CscB.

AlekseyPX

Answer:

Step-by-step explanation:

take angle B as reference angle

using cosec rule

cosec B=hypotenuse/opposite

cosec B=13/12

cosec B=1.08

B=cosec 67

B=67 degree

for ratio,

cosec B=13/12

7 0

2 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

2 years ago

three sets of the sum of a number and four are added to the sum of seven times the same number and thirteen

almond37 [142]

The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

Solution:

Given the statement:

Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen

Let us first understand the given statement,

Let the number be "x"

" sum of a number and four" means x + 4

"Three sets of a sum of a number and four" translated to 3(x + 4)

"sum of seven times the same number and thirteen" means 7x + 13

Thus the algebraic expression for given statement is:

$3(x+4)+(7x + 13)$

Using distributive property in above expression

$a(b+c) = ab + bc$

Therefore,

$3(x+4)+(7x + 13) = 3x + 12 + 7x + 13$

Combine the like terms

$3(x+4)+(7x + 13) = 10x+25$

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

7 0

2 years ago

Help ASAP:Solve : 0.84+91.279

jeka94

Answer:

92.119

Step-by-step explanation:

0.84+91.279=92.119

Hope this helps!

6 0

3 years ago

Read 2 more answers