Ponce is the largest city on which coast of Puerto Rico

windows 10 brought back the desktop, and gives the option to use either the start screen or desktop with a new tiled___

levacccp [35]

Answer:

A new tiled background

5 0

3 years ago

Write a code that calculates the Greatest Common Divisor (GCD) of two positive integers (user-defined inputs). Include an except

STALIN [3.7K]

Answer:

This program is written using Java programming language

import java.util.*;

public class calcGcd

{

public static void main (String [] args)

{

int num1, num2;

Scanner input = new Scanner(System.in);

//Input two integers

num1 = input.nextInt();

num2 = input.nextInt();

//Get least of the two integers

int least = num1;

if(num1 > num2)

{

least = num2;

}

//Initialize gcd to 1

int gcd = 1;

//Calculate gcd using for loop

for(int i=1;i<=least;i++)

{

if(num1%i == 0 && num2%i == 0)

{

gcd = i;

}

if(gcd == 1)

{

System.out.print("GCD is 1");

}

else

{

System.out.print("GCD is "+gcd);

}

Explanation:

To calculate the GCD, the program uses a for loop that iterates from 1 to the smaller number of the user input.

Within this iteration, the program checks for a common divisor of the two user inputs by the iterating element

The GCD is then displayed afterwards;

However, if the GCD is 1; the program prints the message "GCD is 1"

Line by Line Explanation

This line declares two integer numbers

int num1, num2;

This line allows user the program to accept user defined inputs

Scanner input = new Scanner(System.in);

The next two line allows gets inputs from the user

num1 = input.nextInt();

num2 = input.nextInt();

To calculate the GCD, the smaller of the two numbers is needed. The smaller number is derived using the following if statement

int least = num1;

if(num1 > num2)

{

least = num2;

}

The next line initializes GCD to 1

int gcd = 1;

The GCD is calculated using the following for loop

The GCD is the highest number that can divide both numbers

for(int i=1;i<=least;i++)

{

if(num1%i == 0 && num2%i == 0)

{

gcd = i;

}

The following is printed if the calculated GCD is 1

if(gcd == 1)

{

System.out.print("GCD is 1");

}

Otherwise, the following is printed

else

{

System.out.print("GCD is "+gcd);

}

8 0

3 years ago

Write a program that accepts an integer value called multiplier as user input. Create an array of integers with ARRAY_SIZE eleme

Tasya [4]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

void PrintForward(int myarray[], int size){

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

void PrintBackward(int myarray[], int size){

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

int main(){

const int ARRAY_SIZE = 12;

int multiplier;

cout<<"Multiplier: ";

cin>>multiplier;

int myarray [ARRAY_SIZE];

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

PrintForward(myarray,ARRAY_SIZE);

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

Explanation:

The PrintForward function begins here

void PrintForward(int myarray[], int size){

This iterates through the array in ascending order and print each array element

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

The PrintBackward function begins here

void PrintBackward(int myarray[], int size){

This iterates through the array in descending order and print each array element

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

The main begins here

int main(){

This declares and initializes the array size

const int ARRAY_SIZE = 12;

This declares the multiplier as an integer

int multiplier;

This gets input for the multiplier

cout<<"Multiplier: "; cin>>multiplier;

This declares the array

int myarray [ARRAY_SIZE];

This iterates through the array and populate the array by i * multiplier

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

This calls the PrintForward method

PrintForward(myarray,ARRAY_SIZE);

This calls the PrintBackward method

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

6 0

3 years ago

which of the following is not an e-reader you would use as a alternative to carrying around a set of textbooks?

musickatia [10]

I have a kindle paper white that I downloaded all of my avalible textbook onto if that helps I find it much better then carrying around a bunch of textbooks

4 0

4 years ago

What medium allows for electronic delivery of DTP content without the need for any physical media?

Lostsunrise [7]

Email? Dropbox?...Not sure give one of these a try? Hope this helps

0 0

3 years ago