The equation of a parabola is y=a(x-p)^2+q, where (p,q) are the coordinates of the vertex. The value of p will be your axis of symmetry.
(x+2)^2=0
In order for 0=0
x=-2
So your axis of symmetry is x=-2
Which is an infinite arithmetic sequence? a{10, 30, 90, 270, …} b{100, 200, 300, 400} c{150, 300, 450, 600, …} d{1, 2, 4, 8}
umka21 [38]
Answer:
C
Step-by-step explanation:
An arithmetic sequence has a common difference d between consecutive terms.
Sequence a
30 - 10 = 20
90 - 30 = 60
270 - 90 = 180
This sequence is not arithmetic
Sequence b
200 - 100 = 100
300 - 200 = 100
400 - 300 = 100
This sequence is arithmetic but is finite, that is last term is 400
Sequence c
300 - 150 = 150
450 - 300 = 150
600 - 450 = 150
This sequence is arithmetic and infinite, indicated by ........ within set
Sequence d
2 - 1 = 1
4 - 2 = 2
8 - 4 = 4
This sequence is not arithmetic
Thus the infinite arithmetic sequence is sequence c
Answer:
Given the table:
x y
11 ![1\frac{2}{9} = \frac{11}{9}](https://tex.z-dn.net/?f=1%5Cfrac%7B2%7D%7B9%7D%20%3D%20%5Cfrac%7B11%7D%7B9%7D)
21 ![2\frac{1}{3}=\frac{7}{3}](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B3%7D%3D%5Cfrac%7B7%7D%7B3%7D)
45 5
Since, the quantity x and y are proportional.
Proportional states that:
if y varies directly to x, then equation is of the form y = rx where r is the constant of proportionality.
We have to find the value of r:
Consider any value of x and y from the given table:
Let x = 11 and y = ![\frac{11}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B9%7D)
Substitute the given values we get;
![\frac{11}{9} = r \times 11](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B9%7D%20%3D%20r%20%5Ctimes%2011)
Divide both sides by 11 we get;
![r = \frac{1}{9}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B1%7D%7B9%7D)
Therefore, the value of constant of proportionality ![r = \frac{1}{9}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B1%7D%7B9%7D)
Answer:
Step-by-step explanation: