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3241004551 [841]
3 years ago
11

Which equation represents an inverse variation function that passes through the points (4, 5) and (10, 2)?

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0
It’s not 5/4x or 20x are there any other options?
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Can someone please help explain this to me I don’t get it and it’s due in a few hours, please
Svet_ta [14]

Explanation:

1.angels on a straight line add up to 180degrees

2.when you see the signs at number 6 and 7 it means it is 90 degrees

EG. number 6.it will be 90degrees+29degrees=119degrees remember that all angles on a straight line add up to 180 degrees. to get angel xwy you will subtract 119 degrees from 180 degrees =xwy which is 61 degrees

4 0
3 years ago
Traffic along a stretch of road moves at an average speed that varies inversely with the number of cars on it. When there are 15
RSB [31]

Answer:

37.5 miles per hour

Step-by-step explanation:

The traffic along a stretch road moves at an average speed that carried inversely as the number of cars

Average speed= k/number of cars.

When there are 1,500 cars the average speed is 45

The first step is to calculate the constant k

45= k/1500

k = 1,500 × 45

k= 67,500

Therefore the average speed when there are 1,800 cars can be calculated as follows

Average speed= 67,500/1,800

= 37.5 miles per hour

Hence the average speed is 37.5 moles per hour

7 0
3 years ago
the value of c guaranteed to exist by the Mean Value Theorem for V(x) = x² in the interval [0, 3] is...? a) 1 b) 2 c) 3/2 d) 1/2
lilavasa [31]

Answer:  c) \dfrac{3}{2} .

Step-by-step explanation:

Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

\begin{displaymath}f'(c) = \frac{f(b) - f(a)}{b-a} \cdot\end{displaymath}

Given function : f(x) = x^2

Interval : [0,3]

Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that

f'(c)=\dfrac{f(3)-f(0)}{3-0}\\\\=\dfrac{3^2-0^2}{3}=\dfrac{9}{3}\\\\=3

\Rightarrow\ f'(c)=3\ \ \ ...(i)

Since f'(x)=2x

then, at x=c, f'(c)=2c\ \ \ ...(ii)

From (i) and (ii), we have

2c=3\\\\\Rightarrow\ c=\dfrac{3}{2}

Hence, the correct option is c) \dfrac{3}{2} .

4 0
3 years ago
2: Which equation does not belong with the other three? Explain. Thank you so much in advance.
zmey [24]

Answer:

y=x² +6

Step-by-step explanation:

This is the only 2nd-degree equation in the group: y = x² + 6. The others are linear equations.

4 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST Chang deposited $5000 into an account with a 4.8% annual interest rate, compounded monthly. Assuming that n
Mariulka [41]

Answer:

9.42 years (= 113 months)

Step-by-step explanation:

Use the compound rate interest formula:

A=P(1+\frac{r}{n})^{nt}

where:

  • A = amount
  • P = principal
  • r = interest rate (in decimal format)
  • n = number of times interest is compounded per unit t
  • t = time

Given:

  • A = $7850
  • P = $5000
  • r = 4.8% = 0.048
  • n = 12
  • t = years

\implies 7850=5000(1+\frac{0.048}{12})^{12t}

\implies 7850=5000(1.004)^{12t}

\implies \dfrac{7850}{5000}=(1.004)^{12t}

\implies 1.57=(1.004)^{12t}

Take natural logs:

\implies \ln1.57=\ln(1.004)^{12t}

\implies \ln1.57=12t\ln(1.004)

\implies t=\dfrac{\ln 1.57}{12 \ln1.004}

\implies t=9.42\textsf{ years (nearest hundredth)}

\implies t=113 \textsf{ months}

5 0
2 years ago
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