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Colt1911 [192]
2 years ago
14

Find the slope of the line graphed below.

Mathematics
1 answer:
andrew11 [14]2 years ago
6 0

Answer:

-5/4

Step-by-step explanation:

slope = rise/run

Start at the lower right point. Go up 5. The rise = 5. Go left 4. The run -4.

slope = 5/-4 = -5/4

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What is the value of x?
Marat540 [252]
X = 2. I am pretty sure!


Hope i get brainiest!
3 0
4 years ago
Course Home
NNADVOKAT [17]

Answer:

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The solution is a mixture of two or more substances

- A container of liquid contains 60 oz of solution

- The solution contains pure acid by different concentrations

- (a) 20% (b) 25% (c) 30% (d) 50%

- We want to find the number of ounces of the pure acid in each

 concentration

- Assume that the solution is 100%

- That means 100% represents 60 oz of solution

a)

- The percentage of pure acid is 20%

∵    solution     ⇒     pure acid

        100%               20%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*20}{100}= 12

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

b)

- The percentage of pure acid is 25%

∵    solution    ⇒      pure acid

        100%               25%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*25}{100}= 15

(b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.

c)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               30%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*30}{100}= 18

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

d)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               50%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*50}{100}= 30

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

3 0
3 years ago
How do i divide 36 by .75 and what is the answer
Vlad1618 [11]
0.48 I think it's that
5 0
3 years ago
Read 2 more answers
What is −20÷45−20÷45 ?<br><br><br> A. −25<br><br> B. −16<br><br> C− 1/16<br><br> D. − 1/25
stealth61 [152]
The answer is -25 i just took the test/quiz
7 0
4 years ago
In △ABC acute angles are in the ratio 5:1, i.e. ∠BAC:∠ABC = 5:1. If CH is an altitude and CL is an angle bisector, find m∠HCL.
tekilochka [14]

If m\angle BAC:m\angle ABC=5:1, then m\angla BAC=(5x)^{\circ},\ m\angle ABC=x^{\circ}.

The sum of the measures of the interior angles of the triangle is always 180°, then

m\angle ACB=180^{\circ}-x^{\circ}-(5x)^{\circ}=180^{\circ}-(6x)^{\circ}.

Since CL is bisector, then

m\angle BCL=m\angle ACL=\dfrac{180^{\circ}-(6x)^{\circ}}{2}=90^{\circ}-(3x)^{\circ}.

Consider right triangle ACH. In this triangle

m\angle ACH=180^{\circ}-90^{\circ}-(5x)^{\circ}=90^{\circ}-(5x)^{\circ}.

Now angle HCL has measure

m\angle HCL=m\angle ACL-m\angle ACH=90^{\circ}-(3x)^{\circ}-(90^{\circ}-(5x)^{\circ})=(2x)^{\circ}=2m\angle ABC.

Answer: m\angle HCL=2m\angle ABC.

6 0
4 years ago
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