1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatuchka [14]
3 years ago
5

How can you tell when a quadratic equation has no real solutions?

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0
The answer is that <span>A. when the radicand is negative. Having a negative value inside a radicand sign will indicate that there are no solutions. Because we do not know the square root of a negative value.  The result of this is that </span><span>we cannot evaluate the formula </span>any<span> further.</span>
You might be interested in
(-2,3)(0,8) what is en equation for these points
jenyasd209 [6]

Answer:

The line equation that passes through the given points is          5x – 2y + 16 = 0

Explanation:

Given:

Two points are A(-2, 3) and B(0, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1).............(1)

here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.

Now substitute the values in (1)

y-8 = \frac{(3-8)}{(- 2 - 0)}\times(x- 0)

y-8 = \frac{(- 5)}{(-2)}\times(x)

y-8 =\frac{5}{2}x

2y – 16 = 5x

5x – 2y + 16 = 0

Hence, the line equation that passes through the given points is 5x – 2y + 16 = 0.

4 0
4 years ago
Does anyone know he answers for 2 and 3? Need full work and explanations
torisob [31]

Answer:

this is the answer of 2 and

7 0
3 years ago
HELP MEH NOW PLZ :_(
bulgar [2K]

Answer: hey sup fellow player

Step-by-step explanation: how’s life eh?

5 0
3 years ago
Where do the graphs Of linear equations 2x+3y=4 and 5x+6y=7 intersect
UNO [17]
5x + 6y = 7                         SUBSTITUTION METHOD
2x + 2y = 4 


         5x + 6y = 7                      Solve for either x or y in 1 of the 2 equations.
               - 6y - 6y
     -----------------------
         5x = -6y + 7 
        -----  ------  ----
          5       5      5

          x = -6/5y + 7/5



2(-6/5y + 7/5) + 2y = 4             Substitute the expression you got for x or y into 
-12/5y + 14/5 + 2y = 4              the other equation.
-2/5y + 14/5 = 4 
          - 14/5  - 14/5 
------------------------------
-2/5y = 6/5 
--------  --------
- 2/5y  - 2/5y

y = -3 



5x + 6(-3) = 7                             Plug in the value you got for y in step 2 into the 
5x - 18 = 7                                  equation that you didn't use.
    + 18 + 18
------------------
5x = 25 
---    -----
5       5

x = 5 


(x,y) ⇒ coordinate
(5,-3) ⇒ final answer

4 0
3 years ago
In Jefferson Middle School, 5% of the sixth graders have red hair. If there are 100 sixth graders, how many have red hair?
galben [10]
5 sixth graders have red hair
7 0
3 years ago
Read 2 more answers
Other questions:
  • What’s the answer for <br> 0.3(12x – 16)<br> a. 3.6x-16<br> b.3.6x-4.8
    7·1 answer
  • Solve for x. -6 &gt; 10 - 8.0 Enter your answer as an inequality in the box. Plz help I will mark as branliest if right​
    9·1 answer
  • A sphere has a diameter of 12 meters. What is its exact surface area and its exact volume?
    6·1 answer
  • Which angles are alternate exterior angles?
    11·1 answer
  • What expression is equivalent to 2x+3y-x-(8+1)
    7·1 answer
  • Students at sunnyvale Middle School volunteered to work a 2-hour Shift at a car wash fundraiser. The table shows the number of p
    12·2 answers
  • For what value of x must ABCD be a parallelogram ?
    15·1 answer
  • It’s not A 0.17 !!!!!
    6·2 answers
  • Solve :<br> (10/10 / 2*10-6) x 95/0.2)
    11·1 answer
  • To find the distance across a lake, a
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!