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tatuchka [14]
3 years ago
5

How can you tell when a quadratic equation has no real solutions?

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0
The answer is that <span>A. when the radicand is negative. Having a negative value inside a radicand sign will indicate that there are no solutions. Because we do not know the square root of a negative value.  The result of this is that </span><span>we cannot evaluate the formula </span>any<span> further.</span>
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How? Do you do this??
Gre4nikov [31]
X=5/2,x=2  
i cant explain it but if you got to symbolab.com and input the equation it will solve and show you the steps
5 0
3 years ago
Read 2 more answers
In scientific notation, 76 000 = 7.6x 10".<br> n =
Vikentia [17]

Answer:

4 :)

Step-by-step explanation:

7 0
3 years ago
.....?????...........
Liula [17]

You need 3a^3 to equal a^3, so you would need at subtract 2a^3.

Since the problem is addition, add - 2a^3:

3a^3 + -2a^3 = 3a^3 - 2a^3 = a^3

Then you have -5b^3 and you need it to equal b^^3, so you would need to add 6b^3:

-5b^3 + 6b^3 = b^3

First box would be -2

Second box would be 6

3 0
3 years ago
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
What is this answer
Veronika [31]
1. 2x+8=3x+10
Step 1: Subtract 3x from both sides.
2x+8(-3x)= 3x+10 <span>(-3x)
</span>-x+8=10 
Step 2: Subtract 8 from both sides.
-x+8 (-8) = 10 <span>(-8)
</span>-x=2
Step 3: Divide both sides by -1.
-x/(-1)=2/(-1)
x=-2
Answer= x=-2
2. -3x+9=2x-1
Step 1: Subtract 2x from each side. 
-3x (-2x) +9= 2x-1 <span>(-2x)
</span>-5x+9=-1
Step 2: Subtract 9 from both sides. 
-5x+9 (-9)=-1 (-9)
-5x=-10
Step 3: Divide -5 from both sides. 
-5x/-5= -10/-5
x=2
The answer is 2.
3. 4x-7=5x-6
Step 1: Subtract 5x from both sides.
4x-7 (-5x)= 5x-6 (-5x)
-x-7=-6
Step 2: Add 7 to both sides.
-x-7 (+7)= -6 (+7)
-x=1
Step 3: Divide each side by -1.
-x/-1=1/-1
x=-1
The answer is -1. 
5 0
4 years ago
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