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Paul [167]
3 years ago
13

A straight line passing through A(3,2) and B(5,y) has gradient -2. find the value of y​

Mathematics
2 answers:
astraxan [27]3 years ago
7 0

Step-by-step explanation:

gradient \:  =  \:  \frac{y2 - y1}{x2 - x1}

y2 = y , x2 = 5

y1 = 2 , x1 = 3

- 2 \:  =  \:  \frac{y - 2}{5 - 3}

-4 = y-2 ==> y = -2

Serggg [28]3 years ago
7 0

Answer:

y=-2

Step-by-step explanation:

For a line containing the points (X1,Y1) and (X2,Y2), the gradient/slope is equal to (Y2-Y1)/(X2-X1).

Therefore for a line with gradient -2 and points (3,2) and (5,y), we can say:

-2=(y-2)/(5-3)

-2(2)=y-2

y=-4+2

y=-2

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3 years ago
Given that h(x) = 3x −19, find the value of x that makes h(x) = 71.
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Keywords:

<em>Equation, variable, value, clear </em>

For this case we have an equation with a variable of the form y = h (x). Where h (x) = 3x-19. Given the value ofh (x) = 71, we want to find the value of the variable "x". So, we have:

h (x) = 3x-19\\71 = 3x-19

We must clear "x", for this, we add "19" to both sides of the equation:

71 + 19 = 3x-19 + 19\\90 = 3x

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\frac {90} {3} = \frac {3x} {3}\\30 = x

Thus, the value of the variable "x" is 30.

Answer:

x = 30

Option A

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3 years ago
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Answer:

The horizontal distance from the plane to the tower is 2784.5 feet.

Step-by-step explanation:

From the given question, the height of the control tower is not given. But;

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Tan 12^{0} = \frac{x}{13100}

x = 13100 × Tan 12^{0}

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Therefore, the horizontal distance from the plane to the tower is 2784.5 feet.

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I hope this helps you

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