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Paul [167]
3 years ago
13

A straight line passing through A(3,2) and B(5,y) has gradient -2. find the value of y​

Mathematics
2 answers:
astraxan [27]3 years ago
7 0

Step-by-step explanation:

gradient \:  =  \:  \frac{y2 - y1}{x2 - x1}

y2 = y , x2 = 5

y1 = 2 , x1 = 3

- 2 \:  =  \:  \frac{y - 2}{5 - 3}

-4 = y-2 ==> y = -2

Serggg [28]3 years ago
7 0

Answer:

y=-2

Step-by-step explanation:

For a line containing the points (X1,Y1) and (X2,Y2), the gradient/slope is equal to (Y2-Y1)/(X2-X1).

Therefore for a line with gradient -2 and points (3,2) and (5,y), we can say:

-2=(y-2)/(5-3)

-2(2)=y-2

y=-4+2

y=-2

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Find the sum 49+50+51+52+...+141+142
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Answer:

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Step-by-step explanation:

Hello,

49+50+51+52+...+141+142\\\\=(48+1)+(48+2)+(48+3)+(48+4)+...+(48+93)+(48+94)\\\\=48\times 94+(1+2+3+4+...+93+94)\\\\=48\times 94 + \dfrac{94\times 95}{2}\\\\=47(48\times 2+95)=47\times 191=8977

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Step-by-step explanation:

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2 years ago
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What is the value of x in the equation x - y = 30, when y = 15?<br> O4<br> O 8<br> O 80<br> O 200
olganol [36]

\frac{1}{5}x -  \frac{2}{3} y = 30  \\

Putting the value of Y = 15

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