3. f(-6) = 12+1 =13
f(-2) = 4+1 = 5
f(0) =1
Range {1,5,13}
4. f(-2) = (-2)^3+1 =-7
f(-1) = (-1)^2 +1 =0
f(3) = (3)^3 +1 = 28
Range = {-7,0,28}
5.the sequence is arithmetic
d= -11+19 = 8
an = a1 + d(n-1)
an = -19 +8(n-1)
6.l =w+5
a =l*w
a(w) =(w+5) * w
a(w)= w^2 +5w
f(w) = w^2 +5w
f(8) = 8^2 +5(8)
f(8) = 64 +40
f(8) =104 in^2
Answer:
The random variable (number of toppings ordered on a large pizza) has a mean of 1.14 and a standard deviation of 1.04.
Step-by-step explanation:
<em>The question is incomplete:</em>
<em>The probability distribution is:</em>
<em>x P(x)
</em>
<em>
0 0.30
</em>
<em>1 0.40
</em>
<em>2 0.20
</em>
<em>3 0.06
</em>
<em>4 0.04</em>
The mean can be calculated as:
(pi is the probability of each class, Xi is the number of topping in each class)
The standard deviation is calculated as:
Bottom left. Distributive property
19/20 in simplest form is 0.95
9/16 in simplest form is 0.5625
Answer:
Up 1 and over 3
Step-by-step explanation: