All categories

3 years ago

A coin jar contains 10 quarters, 6 dimes and 8 nickels. Find the probability that two quarters are chosen random from the jar.

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Answer: 0.1630

Step-by-step explanation:

Number of quarters = 10

Number of dimes = 6

Number of nickels = 8

Total number = 10+6+8 = 24

Probability of choosing the first quarter will be: = Number of quarters/Total number of money

= 10/24 = 5/12

Since a quarter has been selected, the total number will reduce to 23 the next time a quarter is choosing and the number of quarters will now be 9. Therefore, the probability of choosing the second quarter will be: = 9/23

Therefore, the probability that two quarters are chosen random from the jar will be:

= 5/12 × 9/23

= 45/276

= 0.1630

You might be interested in

Answer these 2 questions please

Dmitry [639]

Where’s the question?

8 0

3 years ago

Read 2 more answers

Rewrite the expression in the form x

Serga [27]

Answer:

See below (I hope this helps!)

Step-by-step explanation:

When dividing exponential terms of the same base, we can simply subtract the exponents, therefore:

$\frac{x^{6} }{x^{8} } = x^{(6-8)} = x^{-2}$

5 0

3 years ago

Here are the LETTERS that goes with the file A=3 B=4 C=6 D=2

Jlenok [28]

Answer:

I think 120

Step-by-step explanation:

8 0

3 years ago

the table shows the number of minutes Tim has for lunch and study hall. he calculates that these two periods account for 18% of

EleoNora [17]

Tim spends 500 minutes at the school.

Step-by-step explanation:

Given,

Time for lunch = 45 minutes

Time for study hall = 45 minutes

Total = 45+45 = 90 minutes

This represents 18% of the total minutes Tim spend at school.

Let,

x be the total minutes Tim spend at school.

18% of x = 90 minutes

$\frac{18}{100}x=90\\\\0.18x=90$

Dividing both sides by 0.18

$\frac{0.18x}{0.18}=\frac{90}{0.18}\\x=500$

Tim spends 500 minutes at the school.

Keywords: percentage, division

Learn more about division at:

#LearnwithBrainly

5 0

3 years ago

player A led a baseball league in runs batted in for the 2006 regular season. player B. who came in second player to A, had 13 f

Alla [95]

A= player A runs batted in
b= player B runs batted in= a-13

250= a + b
substitute b= a-13 for b

250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a

Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b

Hope this helps! :)

7 0

3 years ago