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3 years ago

A coin jar contains 10 quarters, 6 dimes and 8 nickels. Find the probability that two quarters are chosen random from the jar.

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Answer: 0.1630

Step-by-step explanation:

Number of quarters = 10

Number of dimes = 6

Number of nickels = 8

Total number = 10+6+8 = 24

Probability of choosing the first quarter will be: = Number of quarters/Total number of money

= 10/24 = 5/12

Since a quarter has been selected, the total number will reduce to 23 the next time a quarter is choosing and the number of quarters will now be 9. Therefore, the probability of choosing the second quarter will be: = 9/23

Therefore, the probability that two quarters are chosen random from the jar will be:

= 5/12 × 9/23

= 45/276

= 0.1630

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