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emmainna [20.7K]
2 years ago
6

A coin jar contains 10 quarters, 6 dimes and 8 nickels. Find the probability that two quarters are chosen random from the jar.

Mathematics
1 answer:
aliina [53]2 years ago
3 0

Answer: 0.1630

Step-by-step explanation:

Number of quarters = 10

Number of dimes = 6

Number of nickels = 8

Total number = 10+6+8 = 24

Probability of choosing the first quarter will be: = Number of quarters/Total number of money

= 10/24 = 5/12

Since a quarter has been selected, the total number will reduce to 23 the next time a quarter is choosing and the number of quarters will now be 9. Therefore, the probability of choosing the second quarter will be: = 9/23

Therefore, the probability that two quarters are chosen random from the jar will be:

= 5/12 × 9/23

= 45/276

= 0.1630

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Answer:

The 10% condition would not apply here

Explanation:

The 10% condition is the recommended size of sample from the population to get a non biased result. The 10% condition requires that the sample be not more than 10% of the population.

Tossing a coin is an example of a Bernoulli trial. A Bernoulli trial is one that has two possible outcomes, this face of the coin or the other face of the coin. The 10% condition does not apply to Bernoulli trials that are independent events.

Therefore the 10% condition would not apply here because tossing a coin is an an independent event. An independent event is one with replacement.

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3 years ago
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3 years ago
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To calculate the distance between two points on the coordinate system you have to use the following formula:

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Where

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1 year ago
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Nonamiya [84]

Type into your calculator (if you haven't already): log 54.


My result: was similar to yours.


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