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Eduardwww [97]
3 years ago
12

What is the value of expressions ? 18-2×(4+3)

Mathematics
2 answers:
babunello [35]3 years ago
6 0
18-2*(4+3)
Solve parenthesis first:
18-2*7
Multiplication next
18-14
Solve
4
Katarina [22]3 years ago
3 0
BEDMAS

18-2*(4+3)
= 18-2*(7)
= 18-14
= 4
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The Pythagorean theorem
andre [41]

Answer:

b = 3√37

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

  • a is a leg
  • b is another leg
  • c is the hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

a = <em>b</em>

b = 14

c = 23

<u>Step 2: Find </u><em><u>b</u></em>

  1. Substitute [PT]:                     b² + 14² = 23²
  2. Isolate <em>b </em>term:                      b² = 23² - 14²
  3. Exponents:                           b² = 529 - 196
  4. Subtract:                               b² = 333
  5. Isolate <em>b</em>:                               b = 3√37
4 0
3 years ago
A farmer with 5000 feet of fencing wants to enclose a rectangular field and then divide it into two plots by adding a fence in t
matrenka [14]

Answer:

The required width of the field that would maximize the area is = 1250  feet

Step-by-step explanation:

Given that:

The total fencing length = 5000 ft

Let consider w to be the width and L to be the length.

Then; the perimeter of the rectangular field by assuming a parallel direction is:

P = 3L + 2w

⇒ 3L + 2w = 5000

3L = 5000 - 2w

L = \dfrac{5000}{3} - \dfrac{2w}{3}

Recall that:

The area of the rectangle = L×w

A(w) = ( \dfrac{5000}{3}-\dfrac{2}{3} ) w

A(w) =  \dfrac{5000}{3}w-\dfrac{2}{3}  w^2

Taking the differentiation of both sides with respect to t; we have:

A' (w) = \dfrac{5000}{3} - \dfrac{2}{3} ( 2 w)

A' (w) = \dfrac{5000}{3} - \dfrac{4w}{3}

Then; we set A'(w) to be equal to zero;

So; \dfrac{5000}{3} - \dfrac{4w}{3}=0

5000  = 4w

w = 5000/4

w = 1250

Thus; the required width of the field that would maximize the area is = 1250  feet

Also, the length L = \dfrac{5000}{3} - \dfrac{2w}{3} can now be :

L = \dfrac{5000}{3} - \dfrac{2(1250)}{3}

L = (5000 -2500)/3

L = 2500/3 feet

Suppose, the farmer divides the plot parallel to the width; Then  2500/3 feet = 833.33 feet and the length L = 1250 feet.

8 0
2 years ago
Can someone plz help
omeli [17]
i) 1/2
ii) if by between 13 and 19 it means 14,15,16,17, and 18 it is 5/12
iii) 3/12
iv) 0/12
V) 3/12
6 0
3 years ago
Chloe needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer for
yawa3891 [41]
389.50 minus 197 for parts will give you your answer
5 0
2 years ago
Read 2 more answers
Write 16+32 as a product of 2 factors using the GCF and distributive property.
vovikov84 [41]
This is the answer I think 16(1+2)
7 0
2 years ago
Read 2 more answers
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