Answer:
b = 3√37
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
a = <em>b</em>
b = 14
c = 23
<u>Step 2: Find </u><em><u>b</u></em>
- Substitute [PT]: b² + 14² = 23²
- Isolate <em>b </em>term: b² = 23² - 14²
- Exponents: b² = 529 - 196
- Subtract: b² = 333
- Isolate <em>b</em>: b = 3√37
Answer:
The required width of the field that would maximize the area is = 1250 feet
Step-by-step explanation:
Given that:
The total fencing length = 5000 ft
Let consider w to be the width and L to be the length.
Then; the perimeter of the rectangular field by assuming a parallel direction is:
P = 3L + 2w
⇒ 3L + 2w = 5000
3L = 5000 - 2w

Recall that:
The area of the rectangle = L×w


Taking the differentiation of both sides with respect to t; we have:


Then; we set A'(w) to be equal to zero;
So; 
5000 = 4w
w = 5000/4
w = 1250
Thus; the required width of the field that would maximize the area is = 1250 feet
Also, the length
can now be :

L = (5000 -2500)/3
L = 2500/3 feet
Suppose, the farmer divides the plot parallel to the width; Then 2500/3 feet = 833.33 feet and the length L = 1250 feet.
i) 1/2
ii) if by between 13 and 19 it means 14,15,16,17, and 18 it is 5/12
iii) 3/12
iv) 0/12
V) 3/12
389.50 minus 197 for parts will give you your answer
This is the answer I think 16(1+2)