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3 years ago

ANSWER QUICKLY PLEASE

Mathematics

1 answer:

Jet001 [13]3 years ago

8 0

Answer:

answer below:)

Step-by-step explanation:

sin C= $\frac{opposite side}{hypotenuse side}$ = $\frac{7}{25}$

cos C= $\frac{adjacent side}{hypotenuse side}$ = $\frac{24}{25}$

tan C= $\frac{opposite side}{adjacent side}$ = $\frac{7}{24}$

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I need a answer plzzzz

Brilliant_brown [7]

Answer:

it`s acute because the angle is less than 90 degrees

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2 years ago

In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev

Naya [18.7K]

Answer: d) 0.31

Step-by-step explanation:

Given : In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes.

i.e. $\mu=42.5$ and $\sigma= 5.4$

It is assumed that this is a normally distributed variable.

Let x denotes the time spend by a person on treadmill.

Then, the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

$P(30$

Hence, the required probability = 0.31

Thus , the correct answer = d) 0.31

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3 years ago

Let V be the set of vectors in R2 with the following definition of addition and scalar multiplication:

Maksim231197 [3]

Answer:

See below

Step-by-step explanation:

I will denote your new addition by +', and your new scalar multiplication by * to distinguish them from the usual operations.

1) x+'y=y+'x. Yes: Let x=[a,b] and y=[c,d]. Then x+'y=[0,b+d]=[0,d+b]=y+'x

2) (x+'y)+'z=x+'(y+'z). Yes: Let x=[a,b], y=[c,d], z=[e,f]

Then (x+'y)+'z=[0,b+d]+'[e,f]=[0,(b+d)+f]=[0,b+(d+f)]=[a,b]+'[0,d+f]=x+'(y+'z)

3) There exists an element 0 in V such that x+'0=x for each x in V: No

Take x=[1,0]. Then x+'[a,b]=[0,b]≠[1,0], so 0=[a,b] does not exist (no choice of 0 works for this x)

4) For each x in V, there exists an element -x in V such that x+'(-x)=0. Yes (if 0=[0,0])

Given x=[a,b], take -x=[a,-b]. Then x+'(-x)=[0,b-b]=[0,0]=0.

5) *k(x+y)=(*kx)+'(*ky) for each scalar k and any x and y in V. Yes

Let x=[a,b] and y=[c,d]. Then *k(x+'y)=*k[0,b+d]=[0,k(b+d)]=[0,kb]+[0,kd]=*kx+*ky.

6) (s+t)*x=(*sx)+(*tx) for any scalars s and t and any x in V. Yes

Let x=[a,b]. Then (s+t)*x=[0,(s+t)b]=[0,sb]+[0,tb]=*sx+*tx

7) (*s)(*tx)=*(st)x for any scalars s and t and any x in V. Yes

Let x=[a,b]. Then (*s)(*tx)=*s[0,tb]=[0,stb]=*(st)x

8) *1x=x for all x in V. No

*1[1,2]=[0,2]≠[1,2]

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3 years ago

A middle school principal orders 60 pizzas for a schoolwide pizza party. Each pizza is either cheese,pepperoni, or mushroom. The

mina [271]

18 because if you divide them you'll get it

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3 years ago

Read 2 more answers

Can someone help me out

nordsb [41]

Answer:

nah im just gonna take ur points fam

Step-by-step explanation:

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3 years ago