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Brilliant_brown [7]

3 years ago

13

Whats the profit earned as a function ?

2 answers:

Helen [10]3 years ago

8 0

Sorry I just needed points :(

just olya [345]3 years ago

5 0

A profit function is a function that focuses on business applications. The primary purpose for a business is to sell a product or service in order to make a profit, which is the revenue a company receives for selling a product or service less the cost for creating a product or service.

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Please help!! thank you

Ganezh [65]

I got .00390625 for the answer

8 0

3 years ago

Read 2 more answers

You are planning to make an open rectangular box from a 25-in.-by-49-in. piece of cardboard by cutting congruent squares from

Darya [45]

Answer:

The dimensions of the box are 38.48 x 14.48 x 5.26 in.

Step-by-step explanation:

We will have a piece of cardboard with squares of side x cut from the corners to make a open box.

The volume of the box can be written as:

$V=A\cdot B\cdot x\\\\V=(49-2x)\cdot (25-2x)\cdot x\\\\V=x\cdot (4x^2-2x*(49+25)+49*25)\\\\V=4x^3-148x^2+1225x$

To calculate the maximum volume, we derive and equal to zero

$dV/dx=12x^2-296x+1225=0$

We apply the quadratic equation to know the roots of the equation

$x=\frac{-b\pm\sqrt{b^24ac}}{2a}\\\\x=\frac{296\pm\sqrt{296^2-4*12*1225}}{2*12} =\frac{296\pm\sqrt{87616-58800}}{24}= \frac{296\pm\sqrt{28816}}{24}\\\\x=\frac{296\pm169.75}{24}= 12.333\pm7.073\\\\\\x_1=12.333+7.073=19.406\\\\x_2=12.333-7.073=5.26$

The first solution is physically impossible, as the side that is cut would be bigger than 25.

So the real solution is for x=5.26 in.

Then, the dimensions of the box are:

$A=49-2x=49-2*5.26=49-10.52=38.48\\\\B=25-2x=25-10.52=14.48$

8 0

3 years ago

What is 2 and 1 3rd times 5<br>

DedPeter [7]

2 1/3 = (mixed # x denominator) + numerator/ denominator

= 2x3+1/ 3= 7/3

7/3 x 5= 35/3= 11 2/3

5 0

3 years ago

Read 2 more answers

8. What is the domain of <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%5E%7B2%7D%20%2B20x%2B75%7D" id="TexFormula1" title

antiseptic1488 [7]

Answer:

8. Domain: (-∞, -15) ∪ (-15, -5) ∪ (-5, ∞)

9. Domain: [7/13, ∞)

Range: [1, ∞)

Step-by-step explanation:

<u>Question 8</u>

Given rational function:

$f(x)=\dfrac{x}{x^2+20x+75}$

Factor the denominator of the given rational function:

$\implies x^2+20x+75$

$\implies x^2+5x+15x+75$

$\implies x(x+5)+15(x+5)$

$\implies (x+15)(x+5)$

Therefore:

$f(x)=\dfrac{x}{(x+15)(x+5)}$

<u>Asymptote</u>: a line that the curve gets infinitely close to, but never touches.

The function is <u>undefined</u> when the <u>denominator equals zero</u>:

$x+15=0 \implies x=-15$

$x+5=0 \implies x=-5$

Therefore, there are <u>vertical asymptotes</u> at x = -15 and x = -5.

<u>Domain</u>: set of all possible input values (x-values)

Therefore, the <u>domain of the given rational function</u> is:

(-∞, -15) ∪ (-15, -5) ∪ (-5, ∞)

---------------------------------------------------------------------------------

<u>Question 9</u>

Given function:

$f(x)=\sqrt{13x-7}+1$

<u>Domain</u>: set of all possible input values (x-values)

As the <u>square root of a negative number</u> is <u>undefined</u>:

$\implies 13x-7\geq 0$

$\implies 13x\geq 7$

$\implies x\geq \dfrac{7}{13}$

Therefore, the <u>domain of the given function</u> is:

$\left[\dfrac{7}{13},\infty\right)$

<u>Range</u>: set of all possible output values (y-values)

$\textsf{As }\:\sqrt{13x-7}\geq 0$

$\implies \sqrt{13x-7}+1\geq 1$

Therefore, the <u>range of the given function</u> is:

[1, ∞)

8 0

2 years ago

Find the rate of change

valentinak56 [21]

Answer:

It's A

Step-by-step explanation:

8 0

3 years ago