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den301095 [7]
4 years ago
14

The following random sample from a population whose values were normally distributed was collected.10 8 11 11The 95% confidence

interval for μ is:a. 8.00 to 10.00b. 7.75 to 12.25c. 9.75 to 10.75d. 8.52 to 10.98
Mathematics
1 answer:
Margaret [11]4 years ago
6 0

Answer:

Answer:

B

Step-by-step explanation:

First to find the sample mean

Xbar= summation x/n= 40/4= 10

The sample standard deviation is:

S= √summation(x-xbar)²/ n-1

=√6/3= 1.4142

The degrees of freedom

df= N-1= 4-1= 3

For 95% confidence level, critical value of t

t= 3.182

The 95% confidence interval is:

=Xbar plus or minus t' *8/√n

= 10 plus or minus 3.182(1.4142/√4)

= 10plus or minus 2.25

So 7.75 or 12.25

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Today 90 students bought lunch from the cafeteria. If this was 60% of the students, how many students are there in total?
nlexa [21]

Answer:  <u>150 students</u>

Step-by-step explanation:

Let X be the total number of students.  We are told that:

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Step-by-step explanation:

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3 years ago
Rauol measured the height of 12 different plants in his garden in April. He measured them again in June. What is the difference
jasenka [17]

The question is incomplete. Here is the complete question.

Raoul measured the ehight of 12 different plants in his garden in April. He measured them again in June.

April Heights (in inches) 12 15 23 11 42 45 44 39 12 19 20 12

June Heights (in inches) 45 45 40 43 11 14 12 13 41 40 45 41

What is the difference between the mean height in April and the mean height in June?

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Step-by-step explanation: <u>Mean</u> is the average of a set of numbers.

It is calculated as:

\mu=\frac{\Sigma x}{n}

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x is the numbers in the set

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For heights in April, the mean is:

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For heights in June, the mean os:

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μ₂ = 32.5

The difference between means:

μ₂ - μ₁ = 32.5 - 24.5 = 8.0

The difference between the mean height in April and in June is 8.0 inches.

3 0
3 years ago
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