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Semmy [17]
3 years ago
9

A scuba diver was rising back to the surface after taking photos under water. At 2:50 P.M.,

Mathematics
1 answer:
djverab [1.8K]3 years ago
5 0

Answer:

the answer is 11.6 feet

Step-by-step explanation:

you simply subtract the feet of the depth he was at at 2:55pm from his depth at 2:50pm

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If f(x)=2x-1, find f(a+h)<br> A.) a+h-1<br> B.) 2a+h-1<br> C.) 2a+2h-2<br> D.) 2a+2h-1
nadezda [96]
Since f(x) = 2x - 1, all you need is to replace x with (a+h)

So f(a+h) = 2(a+h) - 1 = 2a + 2h - 1

Answer is D
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3 years ago
I need help with #6 <br> Can u also show work ?
Anit [1.1K]

Answer:

the answer is a when you do the math while b and c and d all keep going bit a stops and can no loneger be changed

Step-by-step explanation:

1. distribute 2 to what is in the parentheses ( you should get x over 3 +10)

2. combine both x over 3

cancel out the x and get 6

your answer wpuld be 6 = 10

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3 years ago
What is the product when 20 3 is multiplied with 9 25 ?
Novay_Z [31]

Answer:

187.775

Step-by-step explanation:

20.3×9.25=

187.775

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3 years ago
Which point is between points C and E?<br> B.<br> R.<br> T<br> A
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3 years ago
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| &lt; 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
2 years ago
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