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Phoenix [80]
2 years ago
11

Solve the following equation by the trial and error method...plzzzz fast ......​

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
3 0

Answer:

the required answers are :

a) x = 4

b) x = 3

c) a = 7

d) x = -15

Step-by-step explanation:

the whole process is given in the solution in attached picture. okay

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At a high school movie night, the refreshments stand sells popcorn and soft drinks. Of the 100 students who came to the movie, 6
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Independent events. Someone does not have to buy popcorn to buy a drink and someone does not have to buy a drink to buy popcorn.
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3 years ago
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Is w = 8 a solution to the equation 5 + w = 58? Explain
sp2606 [1]

No.

Since w = 8, you must replace the variable with the number associated to it.

So, it would be 5 + 8 = 58

5 + 8 is not equal to 58, it is equal to 13.

If you wanted to find out what w was, simply subtract 5 on both sides.

w = 58 - 5

8 0
3 years ago
Can someone help me?
krek1111 [17]
I say..3x1= 3+1= 4 :-)
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2 years ago
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A fair coin is tossed six times. What is the probability that it will be heads every time?
yawa3891 [41]

Answer:

A: 3

Step-by-step explanation:

Hopefully this helps!

6 0
2 years ago
How is the Distributive Property used to simplify operations with scientific notation
Citrus2011 [14]

Answer:

See explanation

Step-by-step explanation:

Let a,b, and c be real numbers.

The distributive property says that:

a(b + c) = ab + ac

Assuming we want to simplify:

10(5*10^{-1}+150*10^{-3})

We apply the distributive property to get:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10+150*10^{-3} \times 10

We can now use rules of exponents to simplify further:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10^{1} +150*10^{-3} \times 10^{1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1 + 1} +150*10^{-3 + 1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{0} +150*10^{-2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2}x {10}^{2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2 + 2}

10(5*10^{-1}+150*10^{-3}) = 5+1.50*10^{0} = 6.5 \times  {10}^{0}

4 0
3 years ago
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