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Margaret [11]
4 years ago
13

Help answer and EXPLAIN STEP BY STEP

Mathematics
1 answer:
pychu [463]4 years ago
7 0

15. (-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

Step 1: Distribute the subtraction sign to all the numbers in the second set of parentheses...

(-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

-k^{3} -5k^{2} +1 - 6k^{3} +k^{2} +2

Step 2: Combine like terms (k^{2}'s go with k^{2}'s)

-k^{3} -5k^{2} + 1 - 6k^{3}+k^{2} +2

-5k^{2} +k^{2}

-4k^{2}

-k^{3} -4k^{2} + 1 - 6k^{3}+2

Step 3: Combine like terms (k^{3}'s go with k^{3}'s)

-k^{3} -4k^{2} + 1 - 6k^{3}+2

-k^{3} + (- 6k^{3})

-7k^{3}

-7k^{3} -4k^{2} + 1 +2

Step 4: Combine like terms (normal numbers go with normal numbers)

-7k^{3} -4k^{2} + 1 +2

1 + 2

3

-7k^{3} -4k^{2} + 3

You were correct!

16. 49m^2 - 84mn + 36n^2

I don't really know how to explain this one but I got: (7m-6n)(7m-6n)

You might be interested in
PLEASE solve both question with each step!!
Shkiper50 [21]

Answer:

6x+10-3x=55

6x-3x=10+55

3x=65

65÷3=21.6

5 0
3 years ago
Read 2 more answers
A. Is the sum of two polynomials always a polynomial? Explain
IgorLugansk [536]

Answer:  The answers for both (a) and (b) is YES.


Step-by-step explanation: A polynomial is an algebraic expression containing   two or more algebraic terms, i.e., the sum of several terms that contain different powers of the same variable or variables with real coefficients.

For example, p(x) = 4x²+x+2 is a polynomial in variable 'x'.

(a) Yes, the sum of two polynomials is again a polynomial. For example,

if p(x) = ax² + bx + c  and  q(x) = dx² + ex + f, where, a, b, c, d, e and f are real numbers, then their sum will be

p(x) + q(x) = (a+d)x²+(b+e)x+(c+f), which is again a polynomial in 'x' with real coefficients.

(b) Yes, the difference of two polynomials is again a polynomial. For example,

p(x) - q(x) = (a-d)x²+(b-e)x+(c-f), which is again a polynomial in 'x' with real coefficients.

Thus, the answer is YES.

6 0
3 years ago
I need help please and I don't understand it
UNO [17]
The intercept is (0, -9).

This is the y-intercept. To find the x-intercept, 

5^x = 9.

(1.365, 0)
4 0
3 years ago
PLS HELP TYSM WILL GIVE BRAINLIEST
Shkiper50 [21]

Answer:

2x - 3y

Step-by-step explanation:

-1/4(-8x+12y) = 2x - 3y

4 0
3 years ago
Jennifer serves the volleyball to Marsha with an upward velocity of 10.5 ft/s. The ball is 5 feet above the ground when she stri
Katarina [22]

Answer:

  0.98 seconds

Step-by-step explanation:

We assume the height of the volleyball is described by the equation for ballistic motion. We want to find the time it takes for the height to become zero.

__

<h3>motion equation</h3>

The general form of the equation of height for ballistic motion is ...

  h(t)=-16t^2+v_0t+h_0\qquad\text{$v_0$ and $h_0$ are the initial velocity and height}

The coefficient 16 in the equation is an approximation of 1/2g, where g is the acceleration due to gravity in ft/s². This means the units of time and distance are expected to be seconds and feet.

For the problem at hand, the initial velocity and height are 10.5 ft/s and 5 ft. Then the height equation is ...

  h(t) = -16t² +10.5t +5

__

<h3>reaction time</h3>

Marsha has until the ball hits the ground to react to the serve. To find out how long that is, we need to solve the height equation for t when h=0. This is most easily done using the quadratic formula with ...

  • a = -16
  • b = 10.5
  • c = 5

The solution is ...

  t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}= \dfrac{-10.5\pm\sqrt{10.5^2-4(-16)(5)}}{2(-16)}\\\\=\dfrac{10.5\pm\sqrt{430.25}}{32}=\dfrac{21\pm\sqrt{1721}}{64}

The positive solution is ...

  t ≈ 0.976327 ≈ 0.98

Marsha has about 0.98 seconds to react before the volleyball hits the ground.

_____

<em>Additional comment</em>

After about 0.33 seconds, Marsha knows she doesn't need to react at all. The serve will not clear the net. Its maximum height is about 6' 8 5/8". A women's volleyball net is 7' 4 1/8" high. Jennifer's serve velocity must be at least 12.3 ft/s for the ball to go over the net. With that upward velocity, Marsha has about 1.06 seconds to react.

4 0
2 years ago
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