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Sergio039 [100]
3 years ago
8

You have two cans of paint, Can A and Can B. Can A contains 80% red paint and 20% blue. Can B contains half blue and half red. H

ow much blue paint should be added to 3 liters of Can A to make it the same as Can B?
Mathematics
1 answer:
Digiron [165]3 years ago
3 0

Answer:

0.9 liters.

Step-by-step explanation:

The difference between 20% of 3 and 50% of 3 is 30%. 30% of 3 liters is 0.9 liters so this is what you add to can A.

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Bess [88]
If it helps you any

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}

\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}

so.. check coefficients C and B for the horizontal shift
7 0
4 years ago
Read 2 more answers
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