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Anni [7]
3 years ago
13

What is the value of x and y if 21x+7y=42 and -5x+5y=10 are equal

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

-5x/5 +5y/5=10/5=2

y-x=2

y=x+2

21x+7*(x+2)=42

21x+7x+14=42

28x=42-14

28x=28

x=1

y=1+2

y=3

Step-by-step explanation:

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Why can't irrational numbers be whole numbers
meriva
Irrational numbers cannot be represented by a ratio of two integers.

All whole numbers, however, can. This can be done by placing the number over 1. For example 0/1, 34/1, 173635278/1.
5 0
3 years ago
A survey of 225 students showed the mean number of hours spent studying per week was 20.6 and the standard deviations was 2.7
LekaFEV [45]

Answer:

The margin of error is approximately 0.3

Step-by-step explanation:

The following information has been provided;

The sample size, n =225 students

The sample mean number of hours spent studying per week = 20.6

The standard deviation = 2.7

The question requires us to determine the margin of error that would be associated with a 90% confidence level. In constructing confidence intervals of the population mean, the margin of error is defined as;

The product of the associated z-score and the standard error of the sample mean. The standard error of the sample mean is calculated as;

\frac{sigma}{\sqrt{n} }

where sigma is the standard deviation and n the sample size. The z-score associated with a 90% confidence level, from the given table, is 1.645.

The margin of error is thus;

1.645*\frac{2.7}{\sqrt{225}}=0.2961

Therefore, the margin of error is approximately 0.3

5 0
3 years ago
Read 2 more answers
If ZMK APY, m M = 112 ° , m Y = 41 ° , m K = (13x 37) ° , and m A = (2y + 7) ° , find the values of x and y.
Lunna [17]

Answer

13x-37=112

13x =149

X=11.4

2y+7=41

Y=24

5 0
2 years ago
Read 2 more answers
There are 750 people at a football game. Out of this number, 320 are students. What percent of the people at the football game a
zlopas [31]

Answer:

I have no clue

Step-by-step explanation:

i dont lnow

6 0
3 years ago
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.

49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52

For the median you want o line all of your number up from least to greatest and then find the middle number.

49,49,49,52,54,55,55

Your median is 52

The mode is the number that is listed most often

49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times

So, your mode is 49




4 0
3 years ago
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