Answer:
y=−4 and x=5
Step-by-step explanation:
y=−4;y=(
(−2)
5
)(x)−2
Step: Solvey=−4for y:
Step: Substitute−4foryiny=
−2
5
x−2:
y=
−2
5
x−2
−4=
−2
5
x−2
−4+
2
5
x=
−2
5
x−2+
2
5
x(Add 2/5x to both sides)
2
5
x−4=−2
2
5
x−4+4=−2+4(Add 4 to both sides)
2
5
x=2
2
5
x
2
5
=
2
2
5
(Divide both sides by 2/5)
x=5
Answer:
y=−4 and x=5
The point slope form of (-5, 4) and (5, 1) is ![y-4=\frac{-3}{5}(x+5)](https://tex.z-dn.net/?f=y-4%3D%5Cfrac%7B-3%7D%7B5%7D%28x%2B5%29)
<u>Solution:</u>
Given that a line is passing through points (-5,4) and (5,1)
We need to determine point slope form of line
Equation of line passing through point
is given as:
![\mathrm{y}-\mathrm{y}_{1}=\frac{\left(\mathrm{y}_{2}-\mathrm{y}_{1}\right)}{\left(\mathrm{x}_{2}-\mathrm{x}_{1}\right)}\left(\mathrm{x}-\mathrm{x}_{1}\right)](https://tex.z-dn.net/?f=%5Cmathrm%7By%7D-%5Cmathrm%7By%7D_%7B1%7D%3D%5Cfrac%7B%5Cleft%28%5Cmathrm%7By%7D_%7B2%7D-%5Cmathrm%7By%7D_%7B1%7D%5Cright%29%7D%7B%5Cleft%28%5Cmathrm%7Bx%7D_%7B2%7D-%5Cmathrm%7Bx%7D_%7B1%7D%5Cright%29%7D%5Cleft%28%5Cmathrm%7Bx%7D-%5Cmathrm%7Bx%7D_%7B1%7D%5Cright%29)
![\text { In our case } x_{1}=-5, y_{1}=4, x_{2}=5, y_{2}=1](https://tex.z-dn.net/?f=%5Ctext%20%7B%20In%20our%20case%20%7D%20x_%7B1%7D%3D-5%2C%20y_%7B1%7D%3D4%2C%20x_%7B2%7D%3D5%2C%20y_%7B2%7D%3D1)
Substituting given value in (1) we get
![\begin{array}{l}{y-4=\frac{(1-4)}{(5-(-5))}(x-(-5))} \\\\ {=>y-4=\frac{-3}{10}(x-(-5))} \\\\ {=>y-4=\frac{-3}{5}(x+5)}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7By-4%3D%5Cfrac%7B%281-4%29%7D%7B%285-%28-5%29%29%7D%28x-%28-5%29%29%7D%20%5C%5C%5C%5C%20%7B%3D%3Ey-4%3D%5Cfrac%7B-3%7D%7B10%7D%28x-%28-5%29%29%7D%20%5C%5C%5C%5C%20%7B%3D%3Ey-4%3D%5Cfrac%7B-3%7D%7B5%7D%28x%2B5%29%7D%5Cend%7Barray%7D)
Hence the point slope form of line is ![y-4=\frac{-3}{5}(x+5)](https://tex.z-dn.net/?f=y-4%3D%5Cfrac%7B-3%7D%7B5%7D%28x%2B5%29)
Answer should be A hope it helps