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erastovalidia [21]
3 years ago
6

Exercise 2.1.47 Prove that ifA^-1 exists and AX=0 then X =0.

Mathematics
1 answer:
stepan [7]3 years ago
5 0

Answer:

Step-by-step explanation:

If A^{-1} exist, then we have that A^{-1}\cdot A=1.

Therefore, in the case that AX=0, if we multiply both

terms in the equation by A^{-1}, then we have

A \cdot A^{-1}X=A^{-1}0

and so the equation tells us that

X=A\cdot A^{-1}X=A^{-1}0=0.

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3 years ago
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Debora [2.8K]

Answer:

146°

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3 0
3 years ago
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I am Lyosha [343]
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4 years ago
In the inverse variation function, what happens to the output when the
Nookie1986 [14]

Answer:

Option D.

Step-by-step explanation:

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7 0
3 years ago
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Viktor [21]

Answer:

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