Factor expression 10x + 25

Which expression is equivalent to -9x^-1y^-9/-15x^5y^-3? Assume x is not equal to 0,y is not equal to 0

VladimirAG [237]

I am going to assume that "v" is meant to be a "y"
the answer is b. (3)/(5x^6 y^6)

7 0

3 years ago

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What would the answer be???

Korolek [52]

Answer:

The solution is obtained by adding the two equations.

The solution is: (x, y) = ( $- \frac{2}{3}$ , $- \frac{7}{3}$ )

Step-by-step explanation:

We are given two equations with two variables. The strategy is to eliminate one variable and solve for both the variables.

The two equations are:

$7x + y = - 7 \hspace{15mm} \hdots (1)$

$2x - y = 1 \hspace{15mm} \hdots (2)$

Adding both the equations, we get:

$7x + 2x + y - y = - 7 + 1$

$\implies 9x = - 6$

$\implies x = - \frac{2}{3}$

Substituting the value of 'x', we get the value of y.

We substitute in (2). [Can be substituted in any equation].

We get: y = 2x - 1

$\imples y = 2\bigg(\frac{-2}{3}\bigg) - 1$

$\implies -\frac{4}{3} - 1$

$\implies y = -\frac{7}{3}$

So, we get the corresponding values of x and y which is the solution of the two equations.

4 0

3 years ago

If f(x)=6x^2 and g(x)=14x + 4 solve (g o f)(2) Choices: 340 465 336 284

Law Incorporation [45]

The answer is 340

Explanation:

(g o f)(2) = g(f(2))

f(2) = 6(2)² = 24

g(f(2)) = g(24) = 14(24) + 4 = 336 + 4 = 340

8 0

3 years ago

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What is the vertex form of the parabola whose standard form equation is y=5x^2-30x+49

agasfer [191]

Answer:

The vertex is (3,4)

Step-by-step explanation:

To convert a quadratic from

y = a x 2 + b x + c

form to vertex form,

y = a ( x − h ) 2 + k , you use the process of completing the square.

First, we must isolate the x

terms:

y − 49 = 5 x 2 − 30 x + 49 − 49

y − 49 = 5 x 2 − 30 x

We need a leading coefficient of 1

for completing the square, so factor out the current leading coefficient of 2.

y − 49 = 5 ( x 2 − 6 x )

Next, we need to add the correct number to both sides of the equation to create a perfect square. However, because the number will be placed inside the parenthesis on the right side we must factor it by

2

on the left side of the equation. This is the coefficient we factored out in the previous step.

y − 49 + ( 5 ⋅ ? ) = 5 ( x 2 − 6 x + ? )

<- Hint:

62 = 3 ; 3 ⋅ 3 = 9

y − 49 + ( 5 ⋅ 9 ) = 5 ( x 2 − 6 x + 9 )

y− 49 + 45 = 5 ( x 2 − 6 x + 9 )

y − 4 = 5 ( x 2 − 6 x + 9 )

Then, we need to create the square on the right hand side of the equation:

y − 4 = 5 ( x − 3 ) 2

Now, isolate the y term:

y − 4 + 4 = 5 ( x − 3 ) 2 + 4

y − 0 = 5 ( x − 3 ) 2 + 4

The vertex is:

( 3 , 4 )

7 0

3 years ago

A line is represented by the equation y/x-2=3/11. What are the coordinates of some points that line on the line?

Galina-37 [17]

y/x-2=3/11 would be easier to work with if we were to put it into a more standard form, e. g., y = mx + b.

First, add 2 to both sides, to isolate y/x:

y/x = 3/11 + 22/11 = 25/11.

Next, mult. both sides by x, to get y by itself: y = (25/11)x.

This is your function.

Now make a table. You can choose any x values you want, and then calculate y for each one.

x y

0 0

1 25/11

3 (25/11)*3 = 75/11

Then we have three points on this line: (0,0), (1, 25/11), 3, 75/11). You could obtain more by choosing additional x values.

4 0

3 years ago