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zvonat [6]
2 years ago
14

Pink rose plants are on sale for $3 each and white ones for $5 each. A gardener decides to buy 13 in total, choosing more white

plants than pink. If the gardener spent $55, how many white plants did he buy?
Mathematics
1 answer:
Anettt [7]2 years ago
7 0

Answer:

8

Step-by-step explanation:

If the gardener bought more white than pink, that could mean he could have bought 12 white and one pink, 11 white and 2 pink, 10 white and 3 pink, 9 white and 4 pink, 8 white and 5 pink, or 7 white and 6 pink.

If you plug in the numbers, for example with 7 and 6, that would equal $53, which is not correct. Continue to do this with all of the answers.

With 8 white roses and 5 pink roses, this would equal $55 (40+15), which is the answer.

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e 400 trials in which the assistant maintained a neutral expression, the driver stopped in 229 out of the 400 trials. Find a 95%
Fittoniya [83]

Answer:

Step-by-step explanation:

n = 400

Proportion p = 229/400= 0.5725

For 95% confidence interval we use Z value as 1.96

Std error = 0.025

margin of error = 1.96*0.025

Confidence interval 95% = 0.5725±Margin of error

= (0.524, 0.621)

b) When smiled x becomes 277

p = 0.6925

Std error = 0.023

Margin of error= 1.96*0.023

Confidence interval = (0.647, 0.738)

Smiling increases the chances of stopping since mean and conidence interval bounds are showing increasing trend.

6 0
3 years ago
The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All
Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

C_{n}^{r}  =\frac{n!}{r!(n-r)!}

Where n=100 and r=4.

Replacing values, we have

C_{100}^{4}  =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}=  \frac{94,109,400}{24}= 3,921,225

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

3 0
3 years ago
In a school, 2/3 of the students study a language.
Nimfa-mama [501]

Answer:

6:15

Step-by-step explanation:

2/3= 10/15

2/5= 6/15 study french

6:15

6 0
3 years ago
A worker is being raised in a bucket lift at a constant speed of 3 ft/s. When the worker's arms are 10 ft off the ground, her co
sweet [91]
H=3t+10 and h=-16t+15t+6

They will never be at the same height at the same time
7 0
3 years ago
Read 2 more answers
2. Explain how the order of operations determines how you simplify a numeric expression. Be sure to explain the rules for additi
IgorLugansk [536]
P-paratheses (do any math that has parentheses around the numbers) y=(2x5)+25
E-exponents (do the exponents next) y=(2x5)+5^2
M-multiplying. (Basically everything is self explanatory from here to then cuz im lazy to list examples)
Just basically if you don't use PEMDAS, you'll get the wrong answer
4 0
3 years ago
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