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3 years ago

5.A rectangle has a length of 20 centimeters and a width of 4 centimeters. What is the area of the rectangle?

Mathematics

2 answers:

yawa3891 [41]3 years ago

7 0

A = LW
A = 20 * 4
A = 80 cm^2

OleMash [197]3 years ago

6 0

A = l * w
A = 20 * 4
A = 80 cm^2
Letter D

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What are the characteristics of the function f(x)=2(x-4)^5? Check all that apply

GaryK [48]

Answer:

Option B , C , E are characteristics of the function .

Step-by-step explanation:

Given : function f(x)=2(x-4)^5.

To find : What are the characteristics of the function .

Solution : We have given that f(x)=2 $(x-4)^{5}$ .

By the End Point behavior : if the degree is even and leading coefficient is odd of polynomial of function then left end of graph goes down and right goes up.

Since , Option E is correct.

It has degree 5 therefore, function has 5 zeros and atmost 4 maximua or minimum.

Option C is also correct.

By transformation rule it is vertical stretch and shift to right (B )

Therefore, Option B , C , E are characteristics of the function .

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3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

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3 years ago

Graph the line using a point and a slope. Write the equation of each line. A line that passes through the point (0, –3) and para

kiruha [24]

Y + 3 = 1.2(x - 0)

y + 3 = 1.2x - 0

y = 1.2x - 3

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3 years ago

What is the common ratio for the sequence 28,14,7,3.5 ?

wolverine [178]

Answer:

Its 2

Step-by-step explanation:

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3 years ago

Pencils that were selling at three for 25 cents are now on sale at five for 29 cents. How much money, in cents, would you save b

natita [175]

Answer:

We would save $1.52 cents

Step-by-step explanation:

3 the pencil were at sale for 25 cent

1 pencil = 25 cent/3 =8.33 cent per one pencil

5 the pencil were at sale for 29 cent

1 pencil = 29 cent/5 =5.8 cent per one pencil

If we bought 60 pencil in group of 3 for 25 cent

=60/3= 20 pencil

25cents * 20 pencil = 500 cent per 60 pencil

If we bought 60 pencil in group of 5 for 29 cent

=60/5= 12 pencil

29cents * 12 pencil = 348 cent per 60 pencil

From the analysis, the 5 pencil for 29 cent is cheaper are we are going to save: 500-348= 152 cents

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3 years ago