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Gre4nikov [31]
2 years ago
8

For questions 1-2, use the Reciprocal and Quotient Identities to find each value.​

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
8 0

By using the reciprocal identity the value   Sin \theta will be  \dfrac{5}{27}{

<h3>What is Reciprocal and Quotient Identities?</h3>

In trigonometry, quotient identities refer to trig identities that are divided by each other.

So here we have

Cosec\theta = \dfrac{27}{5}

Now we have to find the reciprocal identity,

Sin\theta=\dfrac{1}{Cosec\theta}

Sin\theta}=\dfrac{1}{\dfrac{27} { 5} }

Sin\theta=\dfrac{5}{27}

hence by using the reciprocal identity the value   Sin \theta will be  \dfrac{5}{27}{

To know more about Reciprocating identity follow

brainly.com/question/15769816

#SPJ1

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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Simplify ⇨ 1/x(x+a) + 1/x(x-a)

\large \boxed{\mathbb{ANSWER \: WITH \: EXPLANATION} \downarrow}

\sf\frac { 1 } { x ( x + a ) } + \frac { 1 } { x ( x - a ) } \\

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\boxed{\boxed{ \bf\frac{2}{x^{2}-a^{2}}}}  \\

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