Answer:
<em>R</em><em>M</em>79 608.51
Step-by-step explanation:
First year,
<em>RM</em>505 050.00×5%=<em>RM</em>505 050.00×5/100
=<em>RM</em>25 252.50
second year,
(<em>RM</em>505 050.00+<em>R</em><em>M</em>25 252.50)×5%=<em>RM</em>530 302.50×5/100
=<em>RM</em>26 515.13
third year,
(<em>R</em><em>M</em>530 302.50+<em>R</em><em>M</em>26 515.13)×5%=<em>R</em><em>M</em>556817.63×5/100
=<em>R</em><em>M</em>27840.88
three years interest,
<em>RM</em>25 252.50+<em>RM</em>26 515.13+<em>RM</em>27840.88=<em>RM</em>79608.51
<em><u>I</u></em><em><u> </u></em><em><u>d</u></em><em><u>o</u></em><em><u>n</u></em><em><u>'</u></em><em><u>t</u></em><em><u> </u></em><em><u>k</u></em><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>a</u></em><em><u>t</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>R</u></em><em><u> </u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>R</u></em><em><u>M</u></em><em><u> </u></em>
<em><u>i</u></em><em><u>f</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>R</u></em><em><u> </u></em><em><u>,</u></em><em><u>s</u></em><em><u>o</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em>
<u>H</u><u>o</u><u>p</u><u>e</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>!</u>
Its the last option because anything between 0 to 1 would he smaller than the original
Answer:
10
Step-by-step explanation:
Given that:
Company A:
40 defective out of every 5000
Company B :
30 out of every 6000
To obtain the highest number of defective phones both companies can produce in common :
Factors of :
40 : 2, 4, 5, 8, 10, 20, 40
30 : 2, 3, 5, 6, 10, 15, 30
Hence, highest number of defective phones both companies can produce in common is 10
Answer:
I think the answer is the battery was 19 percent full when the charging began.