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aivan3 [116]
2 years ago
10

The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum?

Mathematics
2 answers:
Serjik [45]2 years ago
6 0

Answer:

2√5

Step-by-step explanation:

Using the formula for calculating resultant

R = √Fx + Fy

\sum Fx = -2sin 45 + 4 cos 45

\sum Fx =  2cos45

\sum Fx = 2(1/√2)

\sum Fx   = 2/√2

Similarly;

\sum Fy = 2 cos 45 + 4 sin45

\sum Fx  = 2(1/√2) + 4(1/√2)

\sum Fx = 6/√2

Magnitude = √(2/√2)²+6/√2)²

Magnitude = √4/2 + 36/2

Magnitude = √2+18

Magnitude = √20

Magnitude = 2√5

Hence the magnitude of their sum is 2√5

Allisa [31]2 years ago
3 0

Answer:

2√5

Step-by-step explanation:

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Solve the inequality and enter your solution as an inequality comparing the
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Answer: x > 20

Step-by-step explanation:

x + 10 > 30

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x > 20

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3 years ago
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Which of the following lists has a mode of 213? / 111, 108, 213, 198, 205/ /212, 215, 213, 211, 220/ /213, 278, 108, 213, 157/ /
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The mode is the most frequent one
The answer is 213, 278 , 108, 213, 157
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2 years ago
Subtract. Your answer should be a polynomial in standard form. a (4r ^ 2 - 3r + 2) - (- r ^ 2 - 3r) =
blsea [12.9K]

Answer:5r2+2

Step-by-step explanation:

Distribute the Negative Sign:

=4r2−3r+2+−1(−r2−3r)

=4r2+−3r+2+−1(−r2)+−1(−3r)

=4r2+−3r+2+r2+3r

Combine Like Terms:

=4r2+−3r+2+r2+3r

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=5r2+2

6 0
3 years ago
Please answer this (photo)
Musya8 [376]

Answer:

y=-3/2x+3

Step-by-step explanation:

The form of the equation of a line in slope intercept form is y=mx+b, where m is the slope and b is the y intercept. The first step is to find the slope of a line. Since it goes down 3 units for every 2 it moves to the right, it has a slope of -3/2. The y intercept is also obviously at (0,3). Therefore, the equation of this line is y=-3/2x+3.

Hope this helps!

3 0
3 years ago
1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene
rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

<em>x² + y²-8x + 10y + 16 = 0 </em>

<em>Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0 </em>

<em> </em>

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

<em>x² + y² + x + 18y + 33 = 0 </em>

<em>Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0</em>

4 0
2 years ago
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