All categories

3 years ago

Are you a robot cause i think you are

Mathematics

2 answers:

natima [27]3 years ago

8 0

No I am not a robot what u mean

sattari [20]3 years ago

5 0

I am not. I’m actually an alien i come from planet Kepler-452b. Don’t know if the world knows my planet yet. They were supposed to find out in 2020 when i arrived

You might be interested in

Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x

Natali [406]

Answer: hello your question is incomplete attached below is the complete question

answer :

a) $\int\limits^3_0 {(10-x)-(x+4)} \, dx$ ( option D )

b) A = 1/2 (6)(3) ( option B )

c) Area of shaded region = 9

Step-by-step explanation:

a) Using integration with respect to x

Area = $\int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy$ ( note a = 10 )

= y^2/2 - 4y |⁷₄ + 10y - y^2/2 |¹⁰₇

= 33/2 - 12 + 30 - 51/2 = 9

hence the best integral from the options attached is option D

$\int\limits^3_0 {(10-x)-(x+4)} \, dx$

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

= 30 - 9/2 - 9/2 - 12 = 9

b) Using Geometry

Area = 1/2 * base * height

= 1/2 * 6 * 3

= 9

7 0

3 years ago

Need help will give thanks and brainliest

Y_Kistochka [10]

Answer:

$y=\frac{2}{3} x-1$

Step-by-step explanation:

Linear equations are typically organized in slope-intercept form:

$y=mx+b$ where $m$ is the slope and $b$ is the y-intercept (the value of y when the line intercepts the y-axis)

1) Find the slope of the line (m)

The equation for slope: $\frac{y_2-y_1}{x_2-x_1}$ when the given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (3,1) and (6,3)

$\frac{y_2-y_1}{x_2-x_1}$

$=\frac{3-1}{6-3}\\=\frac{2}{3}$

Now, plugging this back into $y=mx+b$ , our equation looks like this:

$y=\frac{2}{3} x+b$

2) Find the y-intercept of the line

To find the y-intercept, we take the equation that we have so far and plug in any given point to solve for b. For example, we can use the point (3,1):

$1=\frac{2}{3}*3+b\\1=2+b$

Subtract both sides by 2 to isolate b

$1-2=2+b-2\\-1=b$

3) Plug m and b into y=mx+b

$y=\frac{2}{3} x-1$

I hope this helps!

8 0

3 years ago

Question 18 plz help <3

Karolina [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

A Rube Goldberg machine consists of a series of devices that perform a simple task. Kate is drawing a scale model of her Rube Go

Salsk061 [2.6K]

Answer:

The unit rate is 16

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Question Help

ValentinkaMS [17]

Step-by-step explanation:

We assume that the advertising rates in this journal for full-page ads is x ($/ad); the rate for half-page ads is y ($/ad).

The revenue for 3 full page ads are: 3x ($)

The revenue for 5 half page ads are: 5y ($)

One issue of a journal has 3 full-page ads and 5 half-page ads, generating $6340.

=> The total revenue for 3 full page and 5 half page ads are $6340

=> 3x + 5y = 6340

The revenue for 4 full page ads are: 4x ($)

The revenue for 4 half page ads are: 4y ($)

One issue of a journal has 4 full-page ads and 4 half-page ads, generating $6625.

=> The total revenue for 4 full page and 4 half page ads are $6625

=> 4x + 4y = 6625 (1)

We have:

+) 3x + 5y = 6340

=> 5y = 6340 - 3x

=> y = (6340 - 3x)/5 = 1268 - 0.6x

Replace y = 1268 - 0.6x into (1), we have:

4x + 4y = 6625

⇔4x + 4(1268 - 0.6x) = 6625

⇔ 4x + 5072 - 2.4x = 6625

⇔ 1.6x = 1553

⇔ x = 1553/1.6 = 970.625

=> y = 1268 - 0.6x = 1268 - 0.6*970.625= 1268 - 582.375 = 685.625

So the advertising rate for full page ads is $970.625, for half-page ads is $685.625

7 0

4 years ago